Lifting theory

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Template:Short description In mathematics, lifting theory was first introduced by John von Neumann in a pioneering paper from 1931, in which he answered a question raised by Alfréd Haar.[1] The theory was further developed by Dorothy Maharam (1958)[2] and by Alexandra Ionescu Tulcea and Cassius Ionescu Tulcea (1961).[3] Lifting theory was motivated to a large extent by its striking applications. Its development up to 1969 was described in a monograph of the Ionescu Tulceas.[4] Lifting theory continued to develop since then, yielding new results and applications.

Definitions

A lifting on a measure space (X,Σ,μ) is a linear and multiplicative operator T:L∞(X,Σ,μ)→ℒ∞(X,Σ,μ) which is a right inverse of the quotient map {ℒ∞(X,Σ,μ)→L∞(X,Σ,μ)f↦[f]

where ℒ∞(X,Σ,μ) is the seminormed Lp space of measurable functions and L∞(X,Σ,μ) is its usual normed quotient. In other words, a lifting picks from every equivalence class [f] of bounded measurable functions modulo negligible functions a representative— which is henceforth written T([f]) or T[f] or simply Tf — in such a way that T[1]=1 and for all p∈X and all r,s∈ℝ, T(r[f]+s[g])(p)=rT[f](p)+sT[g](p), T([f]×[g])(p)=T[f](p)×T[g](p).

Liftings are used to produce disintegrations of measures, for instance conditional probability distributions given continuous random variables, and fibrations of Lebesgue measure on the level sets of a function.

Existence of liftings

Theorem. Suppose (X,Σ,μ) is complete.[5] Then (X,Σ,μ) admits a lifting if and only if there exists a collection of mutually disjoint integrable sets in Σ whose union is X. In particular, if (X,Σ,μ) is the completion of a σ-finite[6] measure or of an inner regular Borel measure on a locally compact space, then (X,Σ,μ) admits a lifting.

The proof consists in extending a lifting to ever larger sub-σ-algebras, applying Doob's martingale convergence theorem if one encounters a countable chain in the process.

Strong liftings

Suppose (X,Σ,μ) is complete and X is equipped with a completely regular Hausdorff topology τ⊆Σ such that the union of any collection of negligible open sets is again negligible – this is the case if (X,Σ,μ) is σ-finite or comes from a Radon measure. Then the support of μ, Supp⁡(μ), can be defined as the complement of the largest negligible open subset, and the collection Cb(X,τ) of bounded continuous functions belongs to ℒ∞(X,Σ,μ).

A strong lifting for (X,Σ,μ) is a lifting T:L∞(X,Σ,μ)→ℒ∞(X,Σ,μ) such that Tφ=φ on Supp⁡(μ) for all φ in Cb(X,τ). This is the same as requiring that[7] TU≥(U∩Supp⁡(μ)) for all open sets U in τ.

Theorem. If (Σ,μ) is σ-finite and complete and τ has a countable basis then (X,Σ,μ) admits a strong lifting.

Proof. Let T0 be a lifting for (X,Σ,μ) and U1,U2,… a countable basis for τ. For any point p in the negligible set N:=⋃n{p∈Supp⁡(μ):(T0Un)(p)<Un(p)} let Tp be any character[8] on L∞(X,Σ,μ) that extends the character ϕ↦ϕ(p) of Cb(X,τ). Then for p in X and [f] in L∞(X,Σ,μ) define: (T[f])(p):={(T0[f])(p)p∉NTp[f]p∈N. T is the desired strong lifting.

Application: disintegration of a measure

Suppose (X,Σ,μ) and (Y,Φ,ν) are σ-finite measure spaces (μ,ν positive) and π:X→Y is a measurable map. A disintegration of μ along π with respect to ν is a slew Y∋y↦λy of positive σ-additive measures on (Σ,μ) such that

  1. λy is carried by the fiber π−1({y}) of π over y, i.e. {y}∈Φ and λy((X∖π−1({y}))=0 for almost all y∈Y
  2. for every μ-integrable function f,∫Xf(p)μ(dp)=∫Y(∫π−1({y})f(p)λy(dp))ν(dy)(∗) in the sense that, for ν-almost all y in Y, f is λy-integrable, the function y↦∫π−1({y})f(p)λy(dp) is ν-integrable, and the displayed equality (∗) holds.

Disintegrations exist in various circumstances, the proofs varying but almost all using strong liftings. Here is a rather general result. Its short proof gives the general flavor.

Theorem. Suppose X is a Polish space[9] and Y a separable Hausdorff space, both equipped with their Borel σ-algebras. Let μ be a σ-finite Borel measure on X and π:X→Y a Σ,Φ−measurable map. Then there exists a σ-finite Borel measure ν on Y and a disintegration (*). If μ is finite, ν can be taken to be the pushforward[10] π∗μ, and then the λy are probabilities.

Proof. Because of the polish nature of X there is a sequence of compact subsets of X that are mutually disjoint, whose union has negligible complement, and on which π is continuous. This observation reduces the problem to the case that both X and Y are compact and π is continuous, and ν=π∗μ. Complete Φ under ν and fix a strong lifting T for (Y,Φ,ν). Given a bounded μ-measurable function f, let ⌊f⌋ denote its conditional expectation under π, that is, the Radon-Nikodym derivative of[11] π∗(fμ) with respect to π∗μ. Then set, for every y in Y, λy(f):=T(⌊f⌋)(y). To show that this defines a disintegration is a matter of bookkeeping and a suitable Fubini theorem. To see how the strongness of the lifting enters, note that λy(f⋅φ∘π)=φ(y)λy(f)∀y∈Y,φ∈Cb(Y),f∈L∞(X,Σ,μ) and take the infimum over all positive φ in Cb(Y) with φ(y)=1; it becomes apparent that the support of λy lies in the fiber over y.

See also

References

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  1. ↑ Template:Cite journal
  2. ↑ Template:Cite journal
  3. ↑ Template:Cite journal
  4. ↑ Template:Cite book
  5. ↑ A subset N⊆X is locally negligible if it intersects every integrable set in Σ in a subset of a negligible set of Σ. (X,Σ,μ) is complete if every locally negligible set is negligible and belongs to Σ.
  6. ↑ i.e., there exists a countable collection of integrable sets – sets of finite measure in Σ – that covers the underlying set X.
  7. ↑ U, Supp⁡(μ) are identified with their indicator functions.
  8. ↑ A character on a unital algebra is a multiplicative linear functional with values in the coefficient field that maps the unit to 1.
  9. ↑ A separable space is Polish if its topology comes from a complete metric. In the present situation it would be sufficient to require that X is Suslin, that is, is the continuous Hausdorff image of a Polish space.
  10. ↑ The pushforward π∗μ of μ under π, also called the image of μ under π and denoted π(μ), is the measure ν on Φ defined by ν(A):=μ(π−1(A)) for A in Φ.
  11. ↑ fμ is the measure that has density f with respect to μ