Wozencraft ensemble

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Template:Refimprove In coding theory, the Wozencraft ensemble is a set of linear codes in which most of codes satisfy the Gilbert-Varshamov bound. It is named after John Wozencraft, who proved its existence. The ensemble is described by Template:Harvtxt, who attributes it to Wozencraft. Template:Harvtxt used the Wozencraft ensemble as the inner codes in his construction of strongly explicit asymptotically good code.

Existence theorem

Theorem: Let ε>0. For a large enough k, there exists an ensemble of inner codes Cin1,,CinN of rate 12, where N=qk1, such that for at least (1ε)N values of i,Cini has relative distance Hq1(12ε).

Here relative distance is the ratio of minimum distance to block length. And Hq is the q-ary entropy function defined as follows:

Hq(x)=xlogq(q1)xlogqx(1x)logq(1x).

In fact, to show the existence of this set of linear codes, we will specify this ensemble explicitly as follows: for α𝔽qk{0}, define the inner code

{Cinα:𝔽qk𝔽q2kCinα(x)=(x,αx)

Here we can notice that x𝔽qk and α𝔽qk. We can do the multiplication αx since 𝔽qk is isomorphic to 𝔽qk.

This ensemble is due to Wozencraft and is called the Wozencraft ensemble.

For all x,y𝔽qk, we have the following facts:

  1. Cinα(x)+Cinα(y)=(x,αx)+(y,αy)=(x+y,α(x+y))=Cinα(x+y)
  2. For any a𝔽q,aCinα(x)=a(x,αx)=(ax,α(ax))=Cinα(ax)

So Cinα is a linear code for every α𝔽qk{0}.

Now we know that Wozencraft ensemble contains linear codes with rate 12. In the following proof, we will show that there are at least (1ε)N those linear codes having the relative distance Hq1(12ε), i.e. they meet the Gilbert-Varshamov bound.

Proof

To prove that there are at least (1ε)N number of linear codes in the Wozencraft ensemble having relative distance Hq1(12ε), we will prove that there are at most εN number of linear codes having relative distance <Hq1(12ε) i.e., having distance <Hq1(12ε)2k.

Notice that in a linear code, the distance is equal to the minimum weight of all codewords of that code. This fact is the property of linear code. So if one non-zero codeword has weight <Hq1(12ε)2k, then that code has distance <Hq1(12ε)2k.

Let P be the set of linear codes having distance <Hq1(12ε)2k. Then there are |P| linear codes having some codeword that has weight <Hq1(12ε)2k.

Lemma. Two linear codes Cinα1 and Cinα2 with α1,α2𝔽qk distinct and non-zero, do not share any non-zero codeword.
Proof. Suppose there exist distinct non-zero elements α1,α2𝔽qk such that the linear codes Cinα1 and Cinα2 contain the same non-zero codeword y. Now since yCinα1,y=(y1,α1y1) for some y1𝔽qk and similarly y=(y2,α2y2) for some y2𝔽qk. Moreover since y is non-zero we have y1,y20. Therefore (y1,α1y1)=(y2,α2y2), then y1=y20 and α1y1=α2y2. This implies α1=α2, which is a contradiction.

Any linear code having distance <Hq1(12ε)2k has some codeword of weight <Hq1(12ε)2k. Now the Lemma implies that we have at least |P| different y such that wt(y)<Hq1(12ε)2k (one such codeword y for each linear code). Here wt(y) denotes the weight of codeword y, which is the number of non-zero positions of y.

Denote

S={y : wt(y)<Hq1(12ε)2k}

Then:[1]

|P||S|Volq(Hq1(12ε)2k,2k)Volq(r,n) is the volume of Hamming ball of radius r in [q]nqHq(Hq1(12ε))2kVolq(pn,n)qHq(p)n=q(12ε)2k=qk(12ε)<ε(qk1) for k large enough =εN

So |P|<εN, therefore the set of linear codes having the relative distance Hq1(12ε)2k has at least NεN=(1ε)N elements.

See also

References

Template:Reflist

  1. For the upper bound of the volume of Hamming ball check Bounds on the Volume of a Hamming ball