Tensor product of algebras

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Template:Short descriptionIn mathematics, the tensor product of two algebras over a commutative ring R is also an R-algebra. This gives the tensor product of algebras. When the ring is a field, the most common application of such products is to describe the product of algebra representations.

Definition

Let R be a commutative ring and let A and B be R-algebras. Since A and B may both be regarded as Template:Nowrap, their tensor product

A⊗RB

is also an R-module. The tensor product can be given the structure of a ring by defining the product on elements of the form Template:Nowrap by[1]Template:Sfn

(a1⊗b1)(a2⊗b2)=a1a2⊗b1b2

and then extending by linearity to all of Template:Nowrap. This ring is an R-algebra, associative and unital with the identity element given by Template:Nowrap,[2] where 1A and 1B are the identity elements of A and B. If A and B are commutative, then the tensor product is commutative as well.

The tensor product turns the category of R-algebras into a symmetric monoidal category.Template:Citation needed

Further properties

There are natural homomorphisms from A and B to Template:Nowrap given by[3]

a↦a⊗1B
b↦1A⊗b

These maps make the tensor product the coproduct in the category of commutative R-algebras. The tensor product is not the coproduct in the category of all R-algebras; there the coproduct is given by a more general free product of algebras. Nevertheless, the tensor product of non-commutative algebras can be described by a universal property similar to that of the coproduct:

Hom(A⊗B,X)≅{(f,g)∈Hom(A,X)×Hom(B,X)∣∀a∈A,b∈B:[f(a),g(b)]=0},

where [-, -] denotes the commutator. The natural isomorphism is given by identifying a morphism ϕ:A⊗B→X on the left hand side with the pair of morphisms (f,g) on the right hand side where f(a):=ϕ(a⊗1) and similarly g(b):=ϕ(1⊗b).

Applications

The tensor product of commutative algebras is of frequent use in algebraic geometry. For affine schemes X, Y, Z with morphisms from X and Z to Y, so X = Spec(A), Y = Spec(R), and Z = Spec(B) for some commutative rings A, R, B, the fiber product scheme is the affine scheme corresponding to the tensor product of algebras:

X×YZ=Spec⁡(A⊗RB).

More generally, the fiber product of schemes is defined by gluing together affine fiber products of this form.

Examples

Template:See also

  • The tensor product can be used as a means of taking intersections of two subschemes in a scheme: consider the ℂ[x,y]-algebras ℂ[x,y]/f, ℂ[x,y]/g, then their tensor product is ℂ[x,y]/(f)⊗ℂ[x,y]ℂ[x,y]/(g)≅ℂ[x,y]/(f,g), which describes the intersection of the algebraic curves f = 0 and g = 0 in the affine plane over C.
  • More generally, if A is a commutative ring and I,J⊆A are ideals, then AI⊗AAJ≅AI+J, with a unique isomorphism sending (a+I)⊗(b+J) to ab+I+J.
  • Tensor products can be used as a means of changing coefficients. For example, ℤ[x,y]/(x3+5x2+x−1)⊗ℤℤ/5≅ℤ/5[x,y]/(x3+x−1) and ℤ[x,y]/(f)⊗ℤℂ≅ℂ[x,y]/(f).
  • Tensor products also can be used for taking products of affine schemes over a field. For example, ℂ[x1,x2]/(f(x))⊗ℂℂ[y1,y2]/(g(y)) is isomorphic to the algebra ℂ[x1,x2,y1,y2]/(f(x),g(y)) which corresponds to an affine surface in 𝔸ℂ4 if f and g are not zero.
  • Given R-algebras A and B whose underlying rings are graded-commutative rings, the tensor product A⊗RB becomes a graded commutative ring by defining (a⊗b)(a′⊗b′)=(−1)|b||a′|aa′⊗bb′ for homogeneous a, a′, b, and b′.
  • The tensor product of two matrix algebras is Mm(A)⊗AMn(A)≅Mmn(A), the isomorphism given by extending the Kronecker product of two matrices via the universal property.

See also

Notes

Template:Reflist

References

  1. ↑ Kassel (1995), [[[:Template:Google books]] p. 32].
  2. ↑ Kassel (1995), [[[:Template:Google books]] p. 32].
  3. ↑ Kassel (1995), [[[:Template:Google books]] p. 32].