Tautness (topology)

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Template:Short description In mathematics, particularly in algebraic topology, a taut pair is a topological pair (A,B), whose cohomology modules Hq(A,B;G) are isomorphic to the direct limit of the cohomology modules Hq(U,V;G), with (U,V) a pair of open neighborhoods of (A,B), where the direct limit is induced by inclusion.

Definition

For a topological pair (A,B) in a topological space X, a neighborhood (U,V) of such a pair is defined to be a pair such that U and V are neighborhoods of A and B respectively.

If we collect all neighborhoods of (A,B), then we can form a directed set which is directed downward by inclusion. Hence its cohomology module Hq(U,V;G) is a direct system where G is a module over a ring with unity. If we denote its direct limit by

H¯q(A,B;G)=lim→Hq(U,V;G)

the restriction maps Hq(U,V;G)→Hq(A,B;G) define a natural homomorphism i:H¯q(A,B;G)→Hq(A,B;G).

The pair (A,B) is said to be tautly embedded in X (or a taut pair in X) if i is an isomorphism for all q and G.[1]

Basic properties

  • For pair (A,B) of X, if two of the three pairs (B,∅),(A,∅), and (A,B) are taut in X, so is the third.
  • For pair (A,B) of X, if A,B and X have compact triangulation, then (A,B) in X is taut.
  • If U varies over the neighborhoods of A, there is an isomorphism lim→H¯q(U;G)≃H¯q(A;G).
  • If (A,B) and (A′,B′) are closed pairs in a normal space X, there is an exact relative Mayer-Vietoris sequence for any coefficient module G[2]
⋯→H¯q(A∪A′,B∪B′)→H¯q(A,B)⊕H¯q(A′,B′)→H¯q(A∩A′,B∩B′)→⋯

Note

Since the Čech cohomology and the Alexander-Spanier cohomology are naturally isomorphic on the category of all topological pairs,[4] all of the above properties are valid for Čech cohomology. However, it's not true for singular cohomology (see Example)

Dependence of cohomology theory

Example

Source:[5]

Let X be the subspace of ℝ2⊂S2 which is the union of four sets

A1={(x,y)∣x=0,−2≤y≤1}
A2={(x,y)∣0≤x≤1,y=−2}
A3={(x,y)∣x=1,−2≤y≤0}
A4={(x,y)∣0<x≤1,y=sin⁡2π/x}

The first singular cohomology of X is H1(X;Z)=0 and using the Alexander duality theorem on S2−X, lim→{Hq(U;ℤ)}=ℤ as U varies over neighborhoods of X.

Therefore, lim→{Hq(U;ℤ)}→H1(X;ℤ) is not a monomorphism so that X is not a taut subspace of ℝ2 with respect to singular cohomology. However, since X is closed in ℝ2, it's taut subspace with respect to Alexander cohomology.[6]

See also

References

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