Remez inequality

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In mathematics, the Remez inequality, discovered by the Soviet mathematician Evgeny Yakovlevich Remez Template:Harv, gives a bound on the sup norms of certain polynomials, the bound being attained by the Chebyshev polynomials.

The inequality

Let σ be an arbitrary fixed positive number. Define the class of polynomials πn(σ) to be those polynomials p of degree n for which

|p(x)|≤1

on some set of measure ≥ 2 contained in the closed interval [−1, 1+σ]. Then the Remez inequality states that

supp∈πn(σ)‖p‖∞=‖Tn‖∞

where Tn(x) is the Chebyshev polynomial of degree n, and the supremum norm is taken over the interval [−1, 1+σ].

Observe that Tn is increasing on [1,+∞], hence

‖Tn‖∞=Tn(1+σ).

The R.i., combined with an estimate on Chebyshev polynomials, implies the following corollary: If J ⊂ R is a finite interval, and E ⊂ J is an arbitrary measurable set, then Template:NumBlk for any polynomial p of degree n.

Extensions: Nazarov–Turán lemma

Inequalities similar to (Template:EquationNote) have been proved for different classes of functions, and are known as Remez-type inequalities. One important example is Nazarov's inequality for exponential sums Template:Harv:

Nazarov's inequality. Let
p(x)=∑k=1nakeλkx
be an exponential sum (with arbitrary λk ∈C), and let J ⊂ R be a finite interval, E ⊂ J—an arbitrary measurable set. Then
maxx∈J|p(x)|≤emaxk|ℜλk|mes⁡J(Cmes⁡Jmes⁡E)n−1supx∈E|p(x)|,
where C > 0 is a numerical constant.

In the special case when λk are pure imaginary and integer, and the subset E is itself an interval, the inequality was proved by Pál Turán and is known as Turán's lemma.

This inequality also extends to Lp(𝕋), 0≤p≤2 in the following way

‖p‖Lp(𝕋)≤eA(n−1)mes⁡(𝕋∖E)‖p‖Lp(E)

for some A > 0 independent of p, E, and n. When

mes⁡E<1−log⁡nn

a similar inequality holds for p > 2. For p = ∞ there is an extension to multidimensional polynomials.

Proof: Applying Nazarov's lemma to E=Eλ={x:|p(x)|≤λ}, λ>0 leads to

maxx∈J|p(x)|≤emaxk|ℜλk|mes⁡J(Cmes⁡Jmes⁡Eλ)n−1supx∈Eλ|p(x)|≤emaxk|ℜλk|mes⁡J(Cmes⁡Jmes⁡Eλ)n−1λ

thus

mes⁡Eλ≤Cmes⁡J(λemaxk|ℜλk|mes⁡Jmaxx∈J|p(x)|)1n−1

Now fix a set E and choose λ such that mes⁡Eλ≤12mes⁡E, that is

λ=(mes⁡E2Cmes⁡J)n−1e−maxk|ℜλk|mes⁡Jmaxx∈J|p(x)|

Note that this implies:

  1. mes⁡E∖Eλ≥12mes⁡E.
  2. ∀x∈E∖Eλ:|p(x)|>λ.

Now

∫x∈E|p(x)|pdx≥∫x∈E∖Eλ|p(x)|pdx≥λp12mes⁡E=12mes⁡E(mes⁡E2Cmes⁡J)p(n−1)e−pmaxk|ℜλk|mes⁡Jmaxx∈J|p(x)|p≥12mes⁡Emes⁡J(mes⁡E2Cmes⁡J)p(n−1)e−pmaxk|ℜλk|mes⁡J∫x∈J|p(x)|pdx,

which completes the proof.

Pólya inequality

One of the corollaries of the Remez inequality is the Pólya inequality, which was proved by George Pólya Template:Harv, and states that the Lebesgue measure of a sub-level set of a polynomial p of degree n is bounded in terms of the leading coefficient LC(p) as follows:

mes⁡{x∈ℝ:|P(x)|≤a}≤4(a2LC(p))1/n,a>0.

References