Hadamard regularization

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Template:Renormalization and regularization In mathematics, Hadamard regularization (also called Hadamard finite part or Hadamard's partie finie) is a method of regularizing divergent integrals by dropping some divergent terms and keeping the finite part, introduced by Template:Harvs. Template:Harvs showed that this can be interpreted as taking the meromorphic continuation of a convergent integral.

If the Cauchy principal value integral π’žβˆ«abf(t)tβˆ’xdt(for a<x<b) exists, then it may be differentiated with respect to Template:Mvar to obtain the Hadamard finite part integral as follows: ddx(π’žβˆ«abf(t)tβˆ’xdt)=β„‹βˆ«abf(t)(tβˆ’x)2dt(for a<x<b).

Note that the symbols π’ž and β„‹ are used here to denote Cauchy principal value and Hadamard finite-part integrals respectively.

The Hadamard finite part integral above (for Template:Math) may also be given by the following equivalent definitions: β„‹βˆ«abf(t)(tβˆ’x)2dt=limΞ΅β†’0+{∫axβˆ’Ξ΅f(t)(tβˆ’x)2dt+∫x+Ξ΅bf(t)(tβˆ’x)2dtβˆ’f(x+Ξ΅)+f(xβˆ’Ξ΅)Ξ΅}, β„‹βˆ«abf(t)(tβˆ’x)2dt=limΞ΅β†’0+{∫ab(tβˆ’x)2f(t)((tβˆ’x)2+Ξ΅2)2dtβˆ’Ο€f(x)2Ξ΅βˆ’f(x)2(1bβˆ’xβˆ’1aβˆ’x)}.

The definitions above may be derived by assuming that the function Template:Math is differentiable infinitely many times at Template:Math, that is, by assuming that Template:Math can be represented by its Taylor series about Template:Math. For details, see Template:Harvs. (Note that the term Template:Math in the second equivalent definition above is missing in Template:Harvs but this is corrected in the errata sheet of the book.)

Integral equations containing Hadamard finite part integrals (with Template:Math unknown) are termed hypersingular integral equations. Hypersingular integral equations arise in the formulation of many problems in mechanics, such as in fracture analysis.

Example

Consider the divergent integral βˆ«βˆ’111t2dt=(limaβ†’0βˆ’βˆ«βˆ’1a1t2dt)+(limbβ†’0+∫b11t2dt)=limaβ†’0βˆ’(βˆ’1aβˆ’1)+limbβ†’0+(βˆ’1+1b)=+∞ Its Cauchy principal value also diverges since π’žβˆ«βˆ’111t2dt=limΞ΅β†’0+(βˆ«βˆ’1βˆ’Ξ΅1t2dt+∫Ρ11t2dt)=limΞ΅β†’0+(1Ξ΅βˆ’1βˆ’1+1Ξ΅)=+∞ To assign a finite value to this divergent integral, we may consider β„‹βˆ«βˆ’111t2dt=β„‹βˆ«βˆ’111(tβˆ’x)2dt|x=0=ddx(π’žβˆ«βˆ’111tβˆ’xdt)|x=0 The inner Cauchy principal value is given by π’žβˆ«βˆ’111tβˆ’xdt=limΞ΅β†’0+(βˆ«βˆ’1βˆ’Ξ΅1tβˆ’xdt+∫Ρ11tβˆ’xdt)=limΞ΅β†’0+(ln|Ξ΅+x1+x|+ln|1βˆ’xΞ΅βˆ’x|)=ln|1βˆ’x1+x| Therefore, β„‹βˆ«βˆ’111t2dt=ddx(ln|1βˆ’x1+x|)|x=0=2x2βˆ’1|x=0=βˆ’2 Note that this value does not represent the area under the curve Template:Math, which is clearly always positive. However, it can be seen where this comes from. Recall the Cauchy principal value of this integral, when evaluated at the endpoints, took the form limΞ΅β†’0+(1Ξ΅βˆ’1βˆ’1+1Ξ΅)=+∞

If one removes the infinite components, the pair of 1Ξ΅ terms, that which remains is limΞ΅β†’0+(βˆ’1βˆ’1)=βˆ’2

which equals the value derived above.

References