Green's function

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An animation that shows how Green's functions can be superposed to solve a differential equation subject to an arbitrary source.
If one knows the solution G(x,x′) to a differential equation subject to a point source L̂(x)G(x,x′)=δ(x−x′) and the differential operator L̂(x) is linear, then one can superpose them to build the solution u(x)=∫f(x′)G(x,x′)dx′ for a general source L̂(x)u(x)=f(x).

In mathematics, a Green's function (or Green function[1]) is the impulse response of an inhomogeneous linear differential operator defined on a domain with specified initial conditions or boundary conditions.

This means that if L is a linear differential operator, then

  • the Green's function G is the solution of the equation LG=δ, where δ is Dirac's delta function;
  • the solution of the inhomogeneous problem Ly=f is the convolution, y=(G∗f).

By the superposition principle, given a linear ordinary differential equation (ODE), Template:Nowrap one can first solve Template:Nowrap for each Template:Mvar. If the source is a sum of delta functions, then the solution is a sum of Green's functions as well due to linearity of Template:Mvar. This means that the integral, viewed as a continuous sum, can reconstruct a wide class of sources, f, through the convolution integral. Whenever the integral of f with Template:Nowrap converges, then the solution to the inhomogeneous equation, Template:Nowrap, is given by Template:Nowrap[2]

Green's functions are named after the British mathematician George Green, who first developed the concept in the 1820s. In the modern study of linear partial differential equations, Green's functions are studied largely from the point of view of fundamental solutions instead, which take into account the modern language of the theory of distributions or generalized functions.[2]

Building off of the superposition principle in many-body theory, the term is also used in physics and engineering, specifically in quantum field theory, aerodynamics, aeroacoustics, electrodynamics, seismology and statistical field theory, to refer to various types of correlation functions, even those that do not fit the mathematical definition. In quantum field theory, Green's functions take the role of propagators, also referred to as two-point (correlation) functions.[3]

Definition and uses

A Green's function, Template:Math, of a linear differential operator Template:Math acting on distributions over a subset of the Euclidean space Template:Nowrap at a point Template:Mvar, is any solution of Template:NumBlk where Template:Mvar is the Dirac delta function. This property of a Green's function can be exploited to solve differential equations of the form Template:NumBlk

If the kernel of Template:Math is non-trivial, then the Green's function is not unique. However, in practice, some combination of symmetry, boundary conditions and/or other externally imposed criteria will give a unique Green's function. Green's functions may be categorized by a Green's function number according to the type of boundary conditions being satisfied. Green's functions are not necessarily functions of a real variable but are generally understood in the sense of distributions.

Green's functions are also useful tools in solving wave equations and diffusion equations.[4][5] In quantum mechanics, Green's function of the Hamiltonian is a key concept with important links to the concept of density of states.

The Green's function as used in physics is usually defined with the opposite sign, instead. That is, LG(x,s)=δ(x−s). This definition does not significantly change any of the properties of Green's function due to the evenness of the Dirac delta function.

If the operator is translation invariant, that is, when L has constant coefficients with respect to Template:Mvar, then the Green's function can be taken to be a convolution kernel, that is, G(x,s)=G(x−s). In this case, Green's function is the same as the impulse response of linear time-invariant system theory.

Motivation

Template:See also Loosely speaking, if such a function Template:Mvar can be found for the operator Template:Math, then, if we multiply Template:EquationNote for the Green's function by Template:Math, and then integrate with respect to Template:Mvar, we obtain, ∫LG(x,s)f(s)ds=∫δ(x−s)f(s)ds=f(x). Because the operator L=L(x) is linear and acts only on the variable Template:Mvar (and not on the variable of integration Template:Mvar), one may take the operator L outside of the integration, yielding L(∫G(x,s)f(s)ds)=f(x). This means that Template:NumBlk is a solution to the equation Lu(x)=f(x).

Thus, one may obtain the function Template:Math through knowledge of the Green's function in Template:EquationNote and the source term on the right-hand side in Template:EquationNote. This process relies upon the linearity of the operator Template:Math.

In other words, the solution of Template:EquationNote, Template:Math, can be determined by the integration given in Template:EquationNote. Although Template:Math is known, this integration cannot be performed unless Template:Mvar is also known. The problem now lies in finding the Green's function Template:Mvar that satisfies Template:EquationNote. For this reason, the Green's function is also sometimes called the fundamental solution associated to the operator Template:Math.

Not every operator L admits a Green's function. A Green's function can also be thought of as a right inverse of Template:Math. Aside from the difficulties of finding a Green's function for a particular operator, the integral in Template:EquationNote may be quite difficult to evaluate. However the method gives a theoretically exact result.

This can be thought of as an expansion of Template:Mvar according to a Dirac delta function basis (projecting Template:Mvar over Template:Nowrap and a superposition of the solution on each projection. Such an integral equation is known as a Fredholm integral equation, the study of which constitutes Fredholm theory.

Green's functions for solving non-homogeneous boundary value problems

The primary use of Green's functions in mathematics is to solve non-homogeneous boundary value problems. In modern theoretical physics, Green's functions are also usually used as propagators in Feynman diagrams; the term Green's function is often further used for any correlation function.

Framework

Let L be a Sturm–Liouville operator, a linear differential operator of the form L=ddx[p(x)ddx]+q(x) and let 𝐃 be the vector-valued boundary conditions operator 𝐃u=[α1u′(0)+β1u(0)α2u′(ℓ)+β2u(ℓ)].

Let f(x) be a continuous function in Template:Nowrap Further suppose that the problem Lu=f𝐃u=𝟎 is regular, i.e., the only solution for f(x)=0 for all Template:Mvar isTemplate:Nowrap

Theorem

There is one and only one solution u(x) that satisfiesTemplate:Citation needed Lu=f𝐃u=𝟎 and it is given by u(x)=∫0ℓf(s)G(x,s)ds, where G(x,s) is a Green's function satisfying the following conditions:

  1. G(x,s) is continuous in x and s.
  2. For Template:Nowrap Template:Pad Template:Nowrap
  3. For Template:Nowrap Template:Pad Template:Nowrap
  4. Derivative "jump": Template:Pad Template:Nowrap
  5. Symmetry: Template:Pad Template:Nowrap

Advanced and retarded Green's functions

Template:See also Green's function is not necessarily unique since the addition of any solution of the homogeneous equation to one Green's function results in another Green's function. Therefore, if the homogeneous equation has nontrivial solutions, multiple Green's functions exist. Certain boundary value or initial value problems involve finding a Green's function that is nonvanishing only for s≤x; in this case, the solution is sometimes called a retarded Green's function.[6] Similarly, a Green's function that is nonvanishing only for s≥x is called an advanced Green's function.[7] In such cases, any linear combination of the two Green's functions is also a valid Green's function. Both the advanced and retarded Green's functions are called one-sided, while a Green's function that is nonvanishing for all x in the domain of definition is called two-sided.[8]

The terminology advanced and retarded is especially useful when the variable x corresponds to time. In such cases, the solution provided by the use of the retarded Green's function depends only on the past sources and is causal whereas the solution provided by the use of the advanced Green's function depends only on the future sources and is acausal. In these problems, it is often the case that the causal solution is the physically important one. However, the advanced Green's function is useful in finding solutions to certain inverse problems where sources are to be found from boundary data. The use of advanced and retarded Green's function is especially common for the analysis of solutions of the inhomogeneous electromagnetic wave equation.[9]

Finding Green's functions

Eigenvalue expansions

If a differential operator Template:Math admits a set of eigenvectors Template:Math (i.e., a set of functions Template:Math and scalars Template:Math such that Template:Math ) that is complete, then it is possible to construct a Green's function from these eigenvectors and eigenvalues.

"Complete" means that the set of functions Template:Math satisfies the following completeness relation, δ(x−x′)=∑n=0∞Ψn†(x′)Ψn(x).

Then the following holds, Template:Equation box 1 where † represents complex conjugation.

Applying the operator Template:Math to each side of this equation results in the completeness relation, which was assumed.

The general study of Green's function written in the above form, and its relationship to the function spaces formed by the eigenvectors, is known as Fredholm theory.

There are several other methods for finding Green's functions, including the method of images, separation of variables, and Laplace transforms.[10]

Representations in terms of the Wronskian

Let L be the general linear second-order differential operator defined on [a,b]∈ℝ. We write

Lu(x)=α(x)d2dx2u(x)+β(x)ddxu(x)+γ(x)u(x)=f(x).

Suppose that u1 and u2 together form a basis of linearly independent solutions to the homogeneous problem Lu=0. Given homogeneous boundary conditions for the Green's function G(a,s)=G(b,s)=0, we may construct G(x,s) by requiring u1(a)=0 and u2(b)=0. The Green's function satisfying these conditions, alongside the continuity of G and its derivative "jump", can be written as

G(x,s)={u1(x)u2(s)α(s)𝒲(𝓈),a≤x<su2(x)u1(s)α(s)𝒲(s),s<x≤b

where 𝒲(x)=u1(x)u'2(x)−u1′(x)u2(x) is known as the Wronskian determinant of u1 and u2. Though this is a somewhat limited case, the Wronskian frequently appears in other sets of boundary value problems that require a one-sided (advanced/retarded) Green's function as well, including those with conditions on boundary derivatives (Neumann conditions) or a pair of conditions on a function and its normal derivative on a single boundary (Cauchy conditions).

Combining Green's functions

If the differential operator L can be factored as L=L1L2 then the Green's function of L can be constructed from the Green's functions for L1 and Template:Nowrap G(x,s)=∫G2(x,s1)G1(s1,s)ds1. The above identity follows immediately from taking G(x,s) to be the representation of the right operator inverse of Template:Nowrap analogous to how for the invertible linear operator Template:Nowrap defined by Template:Nowrap is represented by its matrix elements Template:Nowrap

A further identity follows for differential operators that are scalar polynomials of the derivative, Template:Nowrap The fundamental theorem of algebra, combined with the fact that ∂x commutes with itself, guarantees that the polynomial can be factored, putting L in the form: L=∏i=1N(∂x−zi), where zi are the zeros of Template:Nowrap Taking the Fourier transform of LG(x,s)=δ(x−s) with respect to both x and s gives: G^(kx,ks)=δ(kx−ks)∏i=1N(ikx−zi). The fraction can then be split into a sum using a partial fraction decomposition before Fourier transforming back to x and s space. This process yields identities that relate integrals of Green's functions and sums of the same. For example, if L=(∂x+γ)(∂x+α)2 then one form for its Green's function is: G(x,s)=1(γ−α)2Θ(x−s)e−γ(x−s)−1(γ−α)2Θ(x−s)e−α(x−s)+1γ−αΘ(x−s)(x−s)e−α(x−s)=∫Θ(x−s1)(x−s1)e−α(x−s1)Θ(s1−s)e−γ(s1−s)ds1. While the example presented is tractable analytically, it illustrates a process that works when the integral is not trivial (for example, when ∇2 is the operator in the polynomial).

Table of Green's functions

Template:Disputed section

The following table gives an overview of Green's functions of frequently appearing differential operators, where Template:Nowrap Template:Nowrap Θ(t) is the Heaviside step function, Jν(z) is a Bessel function, Iν(z) is a modified Bessel function of the first kind, and Kν(z) is a modified Bessel function of the second kind.[11] Where time (Template:Mvar) appears in the first column, the retarded (causal) Green's function is listed.

Differential operator Template:Math Green's function Template:Mvar Example of application
∂tn+1 tnn!Θ(t)
∂t+γ Θ(t)e−γt
(∂t+γ)2 Θ(t)te−γt
∂t2+2γ∂t+ω02 where γ<ω0 Θ(t)e−γtsin⁡(ωt)ω   with   ω=ω02−γ2 1D underdamped harmonic oscillator
∂t2+2γ∂t+ω02 where γ>ω0 Θ(t)e−γtsinh⁡(ωt)ω   with   ω=γ2−ω02 1D overdamped harmonic oscillator
∂t2+2γ∂t+ω02 where γ=ω0 Θ(t)e−γtt 1D critically damped harmonic oscillator
1D Laplace operator d2dx2 (x−s)Θ(x−s)+xα(s)+β(s) 1D Poisson equation
2D Laplace operator ∇2D2=∂x2+∂y2 12πln⁡ρ   with   ρ=x2+y2 2D Poisson equation
3D Laplace operator ∇3D2=∂x2+∂y2+∂z2 −14πr   with   r=x2+y2+z2 Poisson equation
Helmholtz operator ∇3D2+k2 −e−ikr4πr=ik32πrH1/2(2)(kr)=ik4πh0(2)(kr) Template:Br where Hα(2) is the Hankel function of the second kind, and h0(2) is the spherical Hankel function of the second kind stationary 3D Schrödinger equation for free particle
Δ2−k4 12k2(i4H0(1)(kr)−12πK0(kr))Template:Br where H0(1) is the Hankel function of the first kind, and K0 is the modified Bessel function 2D time-harmonic flexural wave equation
Divergence operator ∇⋅𝐆 (−1)1+(d−1)!Γ(d2)2πd/2(|d−2|+δd,2)(𝐱−𝐱0)‖𝐱−𝐱0‖d. Let 𝐆 be a vector field from ℝd to ℝd, and 𝐱,𝐱0∈ℝd with d∈ℕ, such that ∇⋅𝐆=δ. The function, Γ(⋅), is the gamma function, and δd,2 is Kronecker's delta, such that δd,2=0 for d≠2, and δ2,2=1 for d=2. Lastly, ! is the factorial symbol and|⋅| is the absolute value.[12] Examples include the time-independent transport or Continuity equation[13] and source-free Maxwell's equations.
∇2−k2 in n dimensions −(2π)−n/2(kr)n/2−1Kn/2−1(kr) Yukawa potential, Feynman propagator, Screened Poisson equation
∂t2−c2∂x2 12cΘ(ct−x) 1D wave equation
∂t2−c2∇2D2 Θ(ct−ρ)2πcc2t2−ρ2 2D wave equation
D'Alembert operator ◻=1c2∂t2−∇3D2 14πrδ(t−rc) 3D wave equation
∂t−k∂x2 (14πkt)1/2Θ(t)e−x2/4kt 1D diffusion
∂t−k∇2D2 (14πkt)Θ(t)e−ρ2/4kt 2D diffusion
∂t−k∇3D2 (14πkt)3/2Θ(t)e−r2/4kt 3D diffusion
1c2∂t2−∂x2+μ2 12(1−sin⁡μct)[δ(ct−x)+δ(ct+x)]+12μΘ(ct−|x|)J0(μu) Template:Br with u=c2t2−x2 1D Klein–Gordon equation
1c2∂t2−∇2D2+μ2 δ(ct−ρ)4πρ(1+cos⁡(μct))+μ2Θ(ct−ρ)4πsinc⁡(μu) Template:Br with u=c2t2−ρ2 2D Klein–Gordon equation
◻+μ2 14πrδ(t−rc)+μc4πuΘ(ct−r)J1(μu)   with   u=c2t2−r2 3D Klein–Gordon equation
∂t2+2γ∂t−c2∂x2 e−γt2[δ(ct−x)+δ(ct+x)]+e−γt2Θ(ct−|x|)(kI0(ku)+γtuI1(ku)) Template:Br with   u=c2t2−x2 and k=γ/c telegrapher's equation
∂t2+2γ∂t−c2∇2D2 e−γt4πρδ(ct−ρ)(1+e−γt+3γt)+e−γt4πu2Θ(ct−ρ)(ku2−3ctcusinh⁡(ku)+3γtcosh⁡(ku)) Template:Br with   u=c2t2−ρ2 and k=γ/c 2D relativistic heat conduction
∂t2+2γ∂t−c2∇3D2 e−γt20πr2δ(ct−r)(8−3e−γt+2γt+4γ2t2)+ke−γt20πuΘ(ct−r)(kI1(ku)+4γtuI2(ku)) Template:Br with   u=c2t2−r2 and k=γ/c 3D relativistic heat conduction

Green's functions for the Laplacian

Green's functions for linear differential operators involving the Laplacian may be readily put to use using the second of Green's identities.

To derive Green's theorem, begin with the divergence theorem (otherwise known as Gauss's theorem), ∫V∇⋅𝐀dV=∫S𝐀⋅d𝝈̂.

Let 𝐀=φ∇ψ−ψ∇φ and substitute into Gauss' law.

Compute ∇⋅𝐀 and apply the product rule for the ∇ operator, ∇⋅𝐀=∇⋅(φ∇ψ−ψ∇φ)=(∇φ)⋅(∇ψ)+φ∇2ψ−(∇φ)⋅(∇ψ)−ψ∇2φ=φ∇2ψ−ψ∇2φ.

Plugging this into the divergence theorem produces Green's theorem, ∫V(φ∇2ψ−ψ∇2φ)dV=∫S(φ∇ψ−ψ∇φ)⋅d𝝈̂.

Suppose that the linear differential operator Template:Mvar is the Laplacian, ∇2, and that there is a Green's function Template:Mvar for the Laplacian. The defining property of the Green's function still holds, LG(𝐱,𝐱′)=∇2G(𝐱,𝐱′)=δ(𝐱−𝐱′).

Let ψ=G in Green's second identity, see Green's identities. Then, ∫V[φ(𝐱′)δ(𝐱−𝐱′)−G(𝐱,𝐱′)∇′2φ(𝐱′)]d3𝐱′=∫S[φ(𝐱′)∇′G(𝐱,𝐱′)−G(𝐱,𝐱′)∇′φ(𝐱′)]⋅d𝝈̂′.

Using this expression, it is possible to solve Laplace's equation Template:Math or Poisson's equation Template:Math, subject to either Neumann or Dirichlet boundary conditions. In other words, we can solve for Template:Math everywhere inside a volume where either (1) the value of Template:Math is specified on the bounding surface of the volume (Dirichlet boundary conditions), or (2) the normal derivative of Template:Math is specified on the bounding surface (Neumann boundary conditions).

Suppose the problem is to solve for Template:Math inside the region. Then the integral ∫Vφ(𝐱′)δ(𝐱−𝐱′)d3𝐱′ reduces to simply Template:Math due to the defining property of the Dirac delta function and we have φ(𝐱)=−∫VG(𝐱,𝐱′)ρ(𝐱′)d3𝐱′+∫S[φ(𝐱′)∇′G(𝐱,𝐱′)−G(𝐱,𝐱′)∇′φ(𝐱′)]⋅d𝝈̂′.

This form expresses the well-known property of harmonic functions, that if the value or normal derivative is known on a bounding surface, then the value of the function inside the volume is known everywhere.

In electrostatics, Template:Math is interpreted as the electric potential, Template:Math as electric charge density, and the normal derivative ∇φ(𝐱′)⋅d𝝈̂′ as the normal component of the electric field.

If the problem is to solve a Dirichlet boundary value problem, the Green's function should be chosen such that Template:Math vanishes when either Template:Mvar or Template:Mvar is on the bounding surface. Thus only one of the two terms in the surface integral remains. If the problem is to solve a Neumann boundary value problem, it might seem logical to choose Green's function so that its normal derivative vanishes on the bounding surface. However, application of Gauss's theorem to the differential equation defining the Green's function yields ∫S∇′G(𝐱,𝐱′)⋅d𝝈̂′=∫V∇'2G(𝐱,𝐱′)d3𝐱′=∫Vδ(𝐱−𝐱′)d3𝐱′=1, meaning the normal derivative of G(x,x′) cannot vanish on the surface, because it must integrate to 1 on the surface.[14]

The simplest form the normal derivative can take is that of a constant, namely Template:Math, where Template:Math is the surface area of the surface. The surface term in the solution becomes ∫Sφ(𝐱′)∇′G(𝐱,𝐱′)⋅d𝝈̂′=⟨φ⟩S where ⟨φ⟩S is the average value of the potential on the surface. This number is not known in general, but is often unimportant, as the goal is often to obtain the electric field given by the gradient of the potential, rather than the potential itself.

With no boundary conditions, the Green's function for the Laplacian (Green's function for the three-variable Laplace equation) is G(𝐱,𝐱′)=−14π|𝐱−𝐱′|.

Supposing that the bounding surface goes out to infinity and plugging in this expression for the Green's function finally yields the standard expression for electric potential in terms of electric charge density as

Template:Equation box 1

Template:Further

Example

Find the Green function for the following problem, whose Green's function number is X11: Lu=u″+k2u=f(x)u(0)=0,u(π2k)=0.

First step: The Green's function for the linear operator at hand is defined as the solution to Template:NumBlk

If x≠s, then the delta function gives zero, and the general solution is G(x,s)=c1cos⁡kx+c2sin⁡kx.

For x<s, the boundary condition at x=0 implies G(0,s)=c1⋅1+c2⋅0=0,c1=0 if x<s and s≠π2k.

For x>s, the boundary condition at x=π2k implies G(π2k,s)=c3⋅0+c4⋅1=0,c4=0

The equation of G(0,s)=0 is skipped for similar reasons.

To summarize the results thus far: G(x,s)={c2sin⁡kx,for x<s,c3cos⁡kx,for s<x.

Second step: The next task is to determine c2 and Template:Nowrap

Ensuring continuity in the Green's function at x=s implies c2sin⁡ks=c3cos⁡ks

One can ensure proper discontinuity in the first derivative by integrating the defining differential equation (i.e., Template:EquationNote) from x=s−ε to x=s+ε and taking the limit as ε goes to zero. Note that we only integrate the second derivative as the remaining term will be continuous by construction. c3⋅(−ksin⁡ks)−c2⋅(kcos⁡ks)=1

The two (dis)continuity equations can be solved for c2 and c3 to obtain c2=−cos⁡ksk;c3=−sin⁡ksk

So Green's function for this problem is: G(x,s)={−cos⁡ksksin⁡kx,x<s,−sin⁡kskcos⁡kx,s<x.

Further examples

See also

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Footnotes

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References

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Cited works

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