Fibonacci group

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Template:Use dmy dates In mathematics, for a natural number n2, the nth Fibonacci group, denoted F(2,n) or sometimes F(n), is defined by n generators a1,a2,,an and n relations:

  • a1a2=a3,
  • a2a3=a4,
  • an2an1=an,
  • an1an=a1,
  • ana1=a2.

These groups were introduced by John Conway in 1965.

The group F(2,n) is of finite order for n=2,3,4,5,7 and infinite order for n=6 and n8. The infinitude of F(2,9) was proved by computer in 1990.

Kaplansky's unit conjecture

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From a group G and a field K (or more generally a ring), the group ring K[G] is defined as the set of all finite formal K-linear combinations of elements of G − that is, an element a of K[G] is of the form a=gGλgg, where λg=0 for all but finitely many gG so that the linear combination is finite. The (size of the) support of an element a=gλgg in K[G], denoted |suppa|, is the number of elements gG such that λg0, i.e. the number of terms in the linear combination. The ring structure of K[G] is the "obvious" one: the linear combinations are added "component-wise", i.e. as gλgg+gμgg=g(λg+μg)g, whose support is also finite, and multiplication is defined by (gλgg)(hμhh)=g,hλgμhgh, whose support is again finite, and which can be written in the form xGνxx as xG(g,hGgh=xλgμh)x.

Kaplansky's unit conjecture states that given a field K and a torsion-free group G (a group in which all non-identity elements have infinite order), the group ring K[G] does not contain any non-trivial units – that is, if ab=1 in K[G] then a=kg for some kK and gG. Giles Gardam disproved this conjecture in February 2021 by providing a counterexample.[1][2][3] He took K=𝔽2, the finite field with two elements, and he took G to be the 6th Fibonacci group F(2,6). The non-trivial unit α𝔽2[F(2,6)] he discovered has |suppα|=|suppα1|=21.[1]

The 6th Fibonacci group F(2,6) has also been variously referred to as the Hantzsche-Wendt group, the Passman group, and the Promislow group.[1][4]

References

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