Fermat–Catalan conjecture

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Template:Short description Template:Use dmy dates In number theory, the Fermat–Catalan conjecture is a generalization of Fermat's Last Theorem and of Catalan's conjecture. The conjecture states that the equation Template:NumBlk has only finitely many solutions (a, b, c, m, n, k) with distinct triplets of values (am, bn, ck) where a, b, c are positive coprime integers and m, n, k are positive integers satisfying Template:NumBlk The inequality on m, n, and k is a necessary part of the conjecture. Without the inequality there would be infinitely many solutions, for instance with k = 1 (for any a, b, m, and n and with c = am + bn), with m=n=k=2 (for the infinitely many Pythagorean triples), and e.g. 75+3933=77922.

Known solutions

As of 2024, the following ten solutions to equation (1) which meet the criteria of equation (2) are known:[1][2][3]

1m+23=32 (for m>6 to satisfy Eq. 2)
25+72=34
73+132=29
27+173=712
35+114=1222
338+15490342=156133
14143+22134592=657
92623+153122832=1137
177+762713=210639282
438+962223=300429072

The first of these (1m + 23 = 32) is the only solution where one of a, b or c is 1, according to the Catalan conjecture, proven in 2002 by Preda Mihăilescu. While this case leads to infinitely many solutions of (1) (since one can pick any m for m > 6), these solutions only give a single triplet of values (am, bn, ck).

Partial results

It is known by the Darmon–Granville theorem, which uses Faltings' theorem, that for any fixed choice of positive integers m, n and k satisfying (2), only finitely many coprime triples (a, b, c) solving (1) exist.[4][5]Template:Rp However, the full Fermat–Catalan conjecture is stronger as it allows for the exponents m, n and k to vary.

The abc conjecture implies the Fermat–Catalan conjecture.[6]

For a list of results for impossible combinations of exponents, see Beal conjecture#Partial results. Beal's conjecture is true if and only if all Fermat–Catalan solutions have m = 2, n = 2, or k = 2.

Poonen et al.[7][8] list exponent triples where the solutions have been determined:[note 1]   {2,3,7},[8]   {2,3,8},[9][10]   {2,3,9},[11]   {2,2q,3} for prime 7<q<1000 with q≠31,[12]   {2,4,5},[10]   {2,4,6},[9]   (2,4,7),   (2,4,q) for prime q≥211,[13]   (2,n,4),[14][15]   {2,n,n},[16]   {3,3,4},[17]   {3,3,5},[17]   {3,3,q} for 17≤q≤10000,[18]   {3,n,n},[16]   {2n,2n,5},[19]   {n,n,n}.[20][21]   For each of these exponent triples, if there is some solution at all, it is listed among those in section Template:Section link.

Sikora partially used the cluster computers at the Center for Computational Research at University at Buffalo to test all tuples (a,b,c,m,n,k) such that min(m,n,k) ≤ 113 and am, bn, ck < Mmin(m,n,k), where M2 = 271, M3 = 280, M4 = 2100, and M5 = ... = M113 = 2113. He did not find any other solution than those above.[note 2][1]

See also

Notes

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References

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