Euler's sum of powers conjecture

From testwiki
Jump to navigation Jump to search

Template:Short description

In number theory, Euler's conjecture is a disproved conjecture related to Fermat's Last Theorem. It was proposed by Leonhard Euler in 1769. It states that for all integers Template:Mvar and Template:Mvar greater than 1, if the sum of Template:Mvar many Template:Mvarth powers of positive integers is itself a Template:Mvarth power, then Template:Mvar is greater than or equal to Template:Mvar:

a1k+a2k++ank=bknk

The conjecture represents an attempt to generalize Fermat's Last Theorem, which is the special case Template:Math: if a1k+a2k=bk, then Template:Math.

Although the conjecture holds for the case Template:Math (which follows from Fermat's Last Theorem for the third powers), it was disproved for Template:Math and Template:Math. It is unknown whether the conjecture fails or holds for any value Template:Math.

Background

Euler was aware of the equality Template:Nowrap involving sums of four fourth powers; this, however, is not a counterexample because no term is isolated on one side of the equation. He also provided a complete solution to the four cubes problem as in Plato's number Template:Nowrap or the taxicab number 1729.[1][2] The general solution of the equation x13+x23=x33+x43 is

x1=λ(1(a3b)(a2+3b2))x2=λ((a+3b)(a2+3b2)1)x3=λ((a+3b)(a2+3b2)2)x4=λ((a2+3b2)2(a3b))

where Template:Mvar, Template:Mvar and λ are any rational numbers.

Counterexamples

Euler's conjecture was disproven by L. J. Lander and T. R. Parkin in 1966 when, through a direct computer search on a CDC 6600, they found a counterexample for Template:Math.[3] This was published in a paper comprising just two sentences.[3] A total of three primitive (that is, in which the summands do not all have a common factor) counterexamples are known: 1445=275+845+1105+1335141325=(220)5+50275+62375+140685853595=555+31835+289695+852825 (Lander & Parkin, 1966); (Scher & Seidl, 1996); (Frye, 2004).

In 1988, Noam Elkies published a method to construct an infinite sequence of counterexamples for the Template:Math case.[4] His smallest counterexample was 206156734=26824404+153656394+187967604.

A particular case of Elkies' solutions can be reduced to the identity[5][6] (85v2+484v313)4+(68v2586v+10)4+(2u)4=(357v2204v+363)4, where u2=22030+28849v56158v2+36941v331790v4. This is an elliptic curve with a rational point at Template:Math. From this initial rational point, one can compute an infinite collection of others. Substituting Template:Math into the identity and removing common factors gives the numerical example cited above.

In 1988, Roger Frye found the smallest possible counterexample 958004+2175194+4145604=4224814 for Template:Math by a direct computer search using techniques suggested by Elkies. This solution is the only one with values of the variables below 1,000,000.[7]

Generalizations

One interpretation of Plato's number, Template:Nowrap

Template:Main article In 1967, L. J. Lander, T. R. Parkin, and John Selfridge conjectured[8] that if

i=1naik=j=1mbjk,

where Template:Math are positive integers for all Template:Math and Template:Math, then Template:Math. In the special case Template:Math, the conjecture states that if

i=1naik=bk

(under the conditions given above) then Template:Math.

The special case may be described as the problem of giving a partition of a perfect power into few like powers. For Template:Math and Template:Math or Template:Math, there are many known solutions. Some of these are listed below.

See Template:OEIS2C for more data.

Template:Nowrap (Plato's number 216)
This is the case Template:Math, Template:Math of Srinivasa Ramanujan's formula[9]

(3a2+5ab5b2)3+(4a24ab+6b2)3+(5a25ab3b2)3=(6a24ab+4b2)3

A cube as the sum of three cubes can also be parameterized in one of two ways:[9]

a3(a3+b3)3=b3(a3+b3)3+a3(a32b3)3+b3(2a3b3)3a3(a3+2b3)3=a3(a3b3)3+b3(a3b3)3+b3(2a3+b3)3

The number 2 100 0003 can be expressed as the sum of three cubes in nine different ways.[9]

4224814=958004+2175194+41456043534=304+1204+2724+3154 (R. Frye, 1988);[4] (R. Norrie, smallest, 1911).[8]

1445=275+845+1105+1335725=195+435+465+475+675945=215+235+375+795+8451075=75+435+575+805+1005

(Lander & Parkin, 1966);[10][11][12] (Lander, Parkin, Selfridge, smallest, 1967);[8] (Lander, Parkin, Selfridge, second smallest, 1967);[8] (Sastry, 1934, third smallest).[8]

It has been known since 2002 that there are no solutions for Template:Math whose final term is ≤ 730000.[13]

5687=1277+2587+2667+4137+4307+4397+5257

(M. Dodrill, 1999).[14]

14098=908+2238+4788+5248+7488+10888+11908+13248

(S. Chase, 2000).[15]

See also

References

Template:Reflist

Template:Leonhard Euler