Debye function

Template:Short description In mathematics, the family of Debye functions is defined by $$D_n(x)=\frac{n}{x^n}\underset{0}{\overset{x}{\int }}\frac{t^n}{e^t-1}dt.$$

The functions are named in honor of Peter Debye, who came across this function (with n = 3) in 1912 when he analytically computed the heat capacity of what is now called the Debye model.

Mathematical properties

Relation to other functions

The Debye functions are closely related to the polylogarithm.

Series expansion

They have the series expansion $$D_n(x)=1-\frac{n}{2(n+1)}x+n\sum _{k=1}^{\mathrm{\infty }}\frac{B_{2k}}{(2k+n)(2k)!}{x}^{2k},|x|<2\pi ,n\ge 1,$$ where $B_n$ is the Template:Mvar-th Bernoulli number.

Limiting values

$$\underset{x\to 0}{\lim }{D}_n(x)=1.$$ If $\mathrm{\Gamma }$ is the gamma function and $\zeta$ is the Riemann zeta function, then, for $x\gg 0$, $$D_n(x)=\frac{n}{x^n}\underset{0}{\overset{x}{\int }}\frac{t^{n}dt}{e^t-1}\sim \frac{n}{x^n}\mathrm{\Gamma }(n+1)\zeta (n+1),\mathrm{Re}n>0,$$

Derivative

The derivative obeys the relation $$x{D}_n^{\prime }(x)=n(B(x)-D_n(x)),$$ where $B(x)=x/(e^x-1)$ is the Bernoulli function.

Applications in solid-state physics

The Debye model

The Debye model has a density of vibrational states $$g_{\text{D}}(\omega )=\frac{9{\omega }^2}{{\omega }_{\text{D}}^3},0\le \omega \le {\omega }_{\text{D}}$$ with the Template:Em Template:Math.

Internal energy and heat capacity

Inserting Template:Math into the internal energy $$U=\underset{0}{\overset{\mathrm{\infty }}{\int }}d\omega g(\omega )\hslash \omega n(\omega )$$ with the Bose–Einstein distribution $$n(\omega )=\frac{1}{\exp (\hslash \omega /k_{\text{B}}T)-1}.$$ one obtains $$U=3k_{\text{B}}T{D}_3(\hslash {\omega }_{\text{D}}/k_{\text{B}}T).$$ The heat capacity is the derivative thereof.

Mean squared displacement

The intensity of X-ray diffraction or neutron diffraction at wavenumber q is given by the Debye-Waller factor or the Lamb-Mössbauer factor. For isotropic systems it takes the form $$\exp (-2W(q))=\exp (-q^2⟨u_x^2⟩).$$ In this expression, the mean squared displacement refers to just once Cartesian component Template:Math of the vector Template:Math that describes the displacement of atoms from their equilibrium positions. Assuming harmonicity and developing into normal modes, one obtains $$2W(q)=\frac{{\hslash }^2{q}^2}{6M{k}_{\text{B}}T}\underset{0}{\overset{\mathrm{\infty }}{\int }}d\omega \frac{k_{\text{B}}T}{\hslash \omega }g(\omega )\coth \frac{\hslash \omega }{2k_{\text{B}}T}=\frac{{\hslash }^2{q}^2}{6M{k}_{\text{B}}T}\underset{0}{\overset{\mathrm{\infty }}{\int }}d\omega \frac{k_{\text{B}}T}{\hslash \omega }g(\omega )[\frac{2}{\exp (\hslash \omega /k_{\text{B}}T)-1}+1].$$ Inserting the density of states from the Debye model, one obtains $$2W(q)=\frac{3}{2}\frac{{\hslash }^2{q}^2}{M\hslash {\omega }_{\text{D}}}[2\left(\frac{k_{\text{B}}T}{\hslash {\omega }_{\text{D}}}\right)D_1\left(\frac{\hslash {\omega }_{\text{D}}}{k_{\text{B}}T}\right)+\frac{1}{2}].$$ From the above power series expansion of $D_1$ follows that the mean square displacement at high temperatures is linear in temperature $$2W(q)=\frac{3k_{\text{B}}T{q}^2}{M{\omega }_{\text{D}}^2}.$$ The absence of $\hslash$ indicates that this is a classical result. Because $D_1(x)$ goes to zero for $x\to \mathrm{\infty }$ it follows that for $T=0$ $$2W(q)=\frac{3}{4}\frac{{\hslash }^2{q}^2}{M\hslash {\omega }_{\text{D}}}$$ (zero-point motion).

Further reading

• Template:AS ref
• "Debye function" entry in MathWorld, defines the Debye functions without prefactor n/xⁿ

Implementations

• Template:Cite journal
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• Template:Cite journal Fortran 77 code
• Fortran 90 version
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• C version of the GNU Scientific Library