Brownian motion and Riemann zeta function

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Template:Short description In mathematics, the Brownian motion and the Riemann zeta function are two central objects of study in mathematics originating from different fields - probability theory and analytic number theory - that have mathematical connections between them. The relationships between stochastic processes derived from the Brownian motion and the Riemann zeta function show in a sense intuitively the stochastic behaviour underlying the Riemann zeta function. A representation of the Riemann zeta function in terms of stochastic processes is called a stochastic representation.[1][2]

Brownian Motion and the Riemann Zeta Function

Let ζ(s) denote the Riemann zeta function and Γ the gamma function, then the Riemann xi function is defined as

ξ(s):=12s(s−1)π−s/2Γ(12s)ζ(s)

satisfying the functional equation

ξ(s)=ξ(1−s),∀s∈ℂ.

It turns out that 2ξ(s) describes the moments of a probability distribution μ[2][3]

2ξ(s)=𝔼[Xs]=∫0∞xsdμ(x),∀s∈ℂ

Brownian Bridge and Riemann Zeta Function

In 1987 Marc Yor and Philippe Biane proved that the random variable defined as the difference between the maximum and minimum of a Brownian bridge (bs)0≤s≤1 describes the same distribution. A Brownian bridge is a one-dimensional Brownian motion (Wt)0≤t≤1 conditioned on W0=W1=0.[4] They showed that

X=2π(max0≤s≤1bs−min0≤s≤1bs)

is a solution for the moment equation

2ξ(s)=𝔼[Xs]

However, this is not the only process related to this distribution, for example the Bessel process also gives rise to random variables with the same distribution.

Bessel process and Riemann Zeta Function

A Bessel process Bes⁡(d) of order d is the Euclidean norm of a d-dimensional Brownian motion. The Bes⁡(3) process is defined as

Rt:=(Wt(1))2+(Wt(2))2+(Wt(3))2.

where Wt=(Wt(1),Wt(2),Wt(3)) is a 3-dimensional Brownian motion.

Define the hitting time T1:=inf⁡{t≥0:Rt=1} and let T1~ be an independent hitting time of another Bes⁡(3) process. Define the random variable

N=π2(T1+T1~),

then we have

2ξ(2s)=𝔼[Ns].[5][2]

Distribution

Let φ be the Radon–Nikodym density of the distribution μ, then the density satisfies the equation[2]

φ(t)=2tΘ″(t)+3Θ′(t)

for the theta function[2]

Θ(t)=∑n=−∞∞e−πn2t.

An alternative parametrization G(y):=Θ(y2) yields[5]

h(y)=2yG′(y)+y2G″(y).

with explicit form

h(y)=4y2∑n=1∞π(2πn4y2−3n2)e−πn2y2

where h(y)=2yφ(y2) and

2ξ(s)=∫0∞ys−1h(y)dy.

See also

References