Šidák correction for t-test

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Template:Short description One of the application of Student's t-test is to test the location of one sequence of independent and identically distributed random variables. If we want to test the locations of multiple sequences of such variables, Šidák correction should be applied in order to calibrate the level of the Student's t-test. Moreover, if we want to test the locations of nearly infinitely many sequences of variables, then Šidák correction should be used, but with caution. More specifically, the validity of Šidák correction depends on how fast the number of sequences goes to infinity.

Introduction

Suppose we are interested in Template:Mvar different hypotheses, H1,...,Hm, and would like to check if all of them are true. Now the hypothesis test scheme becomes

Hnull: all of Hi are true;
Halternative: at least one of Hi is false.

Let α be the level of this test (the type-I error), that is, the probability that we falsely reject Hnull when it is true.

We aim to design a test with certain level α.

Suppose when testing each hypothesis Hi, the test statistic we use is ti.

If these ti's are independent, then a test for Hnull can be developed by the following procedure, known as Šidák correction.

Step 1, we test each of Template:Mvar null hypotheses at level 1(1α)1m.
Step 2, if any of these Template:Mvar null hypotheses is rejected, we reject Hnull.

Finite case

For finitely many t-tests, suppose Yij=μi+ϵij,i=1,...,N,j=1,...,n, where for each Template:Mvar, ϵi1,...,ϵin are independently and identically distributed, for each Template:Mvar ϵ1j,...,ϵNj are independent but not necessarily identically distributed, and ϵij has finite fourth moment.

Our goal is to design a test for Hnull:μi=0,i=1,...,N with level Template:Mvar. This test can be based on the t-statistic of each sequences, that is,

ti=Y¯iSi/n,

where:

Y¯i=1nj=1nYij,Si2=1nj=1n(YijY¯i)2.

Using Šidák correction, we reject Hnull if any of the t-tests based on the t-statistics above reject at level 1(1α)1N. More specifically, we reject Hnull when

i{1,,N}:|ti|>ζα,N,

where

P(|Z|>ζα,N)=1(1α)1N,ZN(0,1)

The test defined above has asymptotic level Template:Mvar, because

level=Pnull(reject Hnull)=Pnull(i{1,,N}:|ti|>ζα,N)=1Pnull(i{1,,N}:|ti|ζα,N)=1i=1NPnull(|ti|ζα,N)1i=1NP(|Zi|ζα,N)ZiN(0,1)=α

Infinite case

In some cases, the number of sequences, N, increase as the data size of each sequences, n, increase. In particular, suppose N(n) as n. If this is true, then we will need to test a null including infinitely many hypotheses, that is

Hnull: all of Hi are true, i=1,2,....

To design a test, Šidák correction may be applied, as in the case of finitely many t-test. However, when N(n) as n, the Šidák correction for t-test may not achieve the level we want, that is, the true level of the test may not converges to the nominal level α as n goes to infinity. This result is related to high-dimensional statistics and is proven by Template:Harvtxt.Template:R Specifically, if we want the true level of the test converges to the nominal level α, then we need a restraint on how fast N(n). Indeed,

  • When all of ϵij have distribution symmetric about zero, then it is sufficient to require logN=o(n1/3) to guarantee the true level converges to α.
  • When the distributions of ϵij are asymmetric, then it is necessary to impose logN=o(n1/2) to ensure the true level converges to α.
  • Actually, if we apply bootstrapping method to the calibration of level, then we will only need logN=o(n1/3) even if ϵij has asymmetric distribution.

The results above are based on Central Limit Theorem. According to Central Limit Theorem, each of our t-statistics ti possesses asymptotic standard normal distribution, and so the difference between the distribution of each ti and the standard normal distribution is asymptotically negligible. The question is, if we aggregate all the differences between the distribution of each ti and the standard normal distribution, is this aggregation of differences still asymptotically ignorable?

When we have finitely many ti, the answer is yes. But when we have infinitely many ti, the answer some time becomes no. This is because in the latter case we are summing up infinitely many infinitesimal terms. If the number of the terms goes to infinity too fast, that is, N(n) too fast, then the sum may not be zero, the distribution of the t-statistics can not be approximated by the standard normal distribution, the true level does not converges to the nominal level α, and then the Šidák correction fails.

See also

References

Template:Reflist