Gieseking manifold

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Template:Short description In mathematics, the Gieseking manifold is a cusped hyperbolic 3-manifold of finite volume. It is non-orientable and has the smallest volume among non-compact hyperbolic manifolds, having volume approximately V1.0149416. It was discovered by Template:Harvs.

The Gieseking manifold can be constructed by removing the vertices from a tetrahedron, then gluing the faces together in pairs using affine-linear maps. Label the vertices 0, 1, 2, 3. Glue the face with vertices 0, 1, 2 to the face with vertices 3, 1, 0 in that order. Glue the face 0, 2, 3 to the face 3, 2, 1 in that order. In the hyperbolic structure of the Gieseking manifold, this ideal tetrahedron is the canonical polyhedral decomposition of David B. A. Epstein and Robert C. Penner. Moreover, the angle made by the faces is π/3. The triangulation has one tetrahedron, two faces, one edge and no vertices, so all the edges of the original tetrahedron are glued together.

The Gieseking manifold has a double cover homeomorphic to the figure-eight knot complement. The underlying compact manifold has a Klein bottle boundary, and the first homology group of the Gieseking manifold is the integers.

The Gieseking manifold is a fiber bundle over the circle with fiber the once-punctured torus and monodromy given by (x,y)(x+y,x). The square of this map is Arnold's cat map and this gives another way to see that the Gieseking manifold is double covered by the complement of the figure-eight knot.

Gieseking constant

The volume of the Gieseking manifold is called the Gieseking constant[1] and has a numeral value of approximately:

V=1.01494 16064 09653 62502 12025[2]

It can be given as in a closed form[3] with the Clausen function Cl2(φ) as:

V=Cl2(π3)

This is similar to Catalan's constant G, which also manifests as a volume and can be expressed in terms of the Clausen function:

G=Cl2(π2)=0.91596559

Another closed form expression may be given in terms of the trigamma function:

V=33(ψ1(1/3)2π23)

Integrals for the Gieseking constant are given by

V=02π/3ln(2cos(12x))dx

V=201ln(1+x)(1x)(3+x)dx

which follow from its definition through the Clausen function and[4]

V=32000dx dy dzxyz(x+y+z+1x+1y+1z)2

A further expression is:

V=334(k=01(3k+1)2k=01(3k+2)2)

This gives:

k=01(3k+1)2=2π227+239V

k=01(3k+2)2=2π227239V

which is similar to:

k=01(4k+1)2=π216+12G

k=01(4k+3)2=π21612G

for Catalan's constant G.

See also

References

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