Malgrange–Ehrenpreis theorem

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In mathematics, the Malgrange–Ehrenpreis theorem states that every non-zero linear differential operator with constant coefficients has a Green's function. It was first proved independently by Template:Harvs and Template:Harvs.

This means that the differential equation

P(x1,,x)u(𝐱)=δ(𝐱),

where P is a polynomial in several variables and δ is the Dirac delta function, has a distributional solution u. It can be used to show that

P(x1,,x)u(𝐱)=f(𝐱)

has a solution for any compactly supported distribution f. The solution is not unique in general.

The analogue for differential operators whose coefficients are polynomials (rather than constants) is false: see Lewy's example.

Proofs

The original proofs of Malgrange and Ehrenpreis were non-constructive as they used the Hahn–Banach theorem. Since then several constructive proofs have been found.

There is a very short proof using the Fourier transform and the Bernstein–Sato polynomial, as follows. By taking Fourier transforms the Malgrange–Ehrenpreis theorem is equivalent to the fact that every non-zero polynomial P has a distributional inverse. By replacing P by the product with its complex conjugate, one can also assume that P is non-negative. For non-negative polynomials P the existence of a distributional inverse follows from the existence of the Bernstein–Sato polynomial, which implies that Ps can be analytically continued as a meromorphic distribution-valued function of the complex variable s; the constant term of the Laurent expansion of Ps at s=1 is then a distributional inverse of P.

Other proofs, often giving better bounds on the growth of a solution, are given in Template:Harv, Template:Harv and Template:Harv. Template:Harv gives a detailed discussion of the regularity properties of the fundamental solutions.

A short constructive proof was presented in Template:Harv:

E=1Pm(2η)j=0majeλjηxξ1(P(iξ+λjη)P(iξ+λjη))

is a fundamental solution of P(), i.e., P()E=δ, if Pm is the principal part of P, ηn with Pm(η)0, the real numbers λ0,,λm are pairwise different, and

aj=k=0,kjm(λjλk)1.

References