Bounded set (topological vector space)

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In functional analysis and related areas of mathematics, a set in a topological vector space is called bounded or von Neumann bounded, if every neighborhood of the zero vector can be inflated to include the set. A set that is not bounded is called unbounded.

Bounded sets are a natural way to define locally convex polar topologies on the vector spaces in a dual pair, as the polar set of a bounded set is an absolutely convex and absorbing set. The concept was first introduced by John von Neumann and Andrey Kolmogorov in 1935.

Definition

Suppose X is a topological vector space (TVS) over a field 𝕂.

A subset B of X is called Template:Em or just Template:Em in X if any of the following equivalent conditions are satisfied:

  1. Template:Em: For every neighborhood V of the origin there exists a real r>0 such that BsV[note 1] for all scalars s satisfying |s|r.Template:Sfn
  2. B is absorbed by every neighborhood of the origin.Template:Sfn
  3. For every neighborhood V of the origin there exists a scalar s such that BsV.
  4. For every neighborhood V of the origin there exists a real r>0 such that sBV for all scalars s satisfying |s|r.Template:Sfn
  5. For every neighborhood V of the origin there exists a real r>0 such that tBV for all real 0<tr.Template:Sfn
  6. Any one of statements (1) through (5) above but with the word "neighborhood" replaced by any of the following: "balanced neighborhood," "open balanced neighborhood," "closed balanced neighborhood," "open neighborhood," "closed neighborhood".
    • e.g. Statement (2) may become: B is bounded if and only if B is absorbed by every balanced neighborhood of the origin.Template:Sfn
    • If X is locally convex then the adjective "convex" may be also be added to any of these 5 replacements.
  7. For every sequence of scalars s1,s2,s3, that converges to 0 and every sequence b1,b2,b3, in B, the sequence s1b1,s2b2,s3b3, converges to 0 in X.Template:Sfn
    • This was the definition of "bounded" that Andrey Kolmogorov used in 1934, which is the same as the definition introduced by Stanisław Mazur and Władysław Orlicz in 1933 for metrizable TVS. Kolmogorov used this definition to prove that a TVS is seminormable if and only if it has a bounded convex neighborhood of the origin.Template:Sfn
  8. For every sequence b1,b2,b3, in B, the sequence (1ibi)i=1 converges to 0 in X.Template:Sfn
  9. Every countable subset of B is bounded (according to any defining condition other than this one).Template:Sfn

If is a neighborhood basis for X at the origin then this list may be extended to include:

  1. Any one of statements (1) through (5) above but with the neighborhoods limited to those belonging to .
    • e.g. Statement (3) may become: For every V there exists a scalar s such that BsV.

If X is a locally convex space whose topology is defined by a family 𝒫 of continuous seminorms, then this list may be extended to include:

  1. p(B) is bounded for all p𝒫.Template:Sfn
  2. There exists a sequence of non-zero scalars s1,s2,s3, such that for every sequence b1,b2,b3, in B, the sequence b1s1,b2s2,b3s3, is bounded in X (according to any defining condition other than this one).Template:Sfn
  3. For all p𝒫, B is bounded (according to any defining condition other than this one) in the semi normed space (X,p).
  4. B is weakly bounded, i.e. every continuous linear functional is bounded on B[1]

If X is a normed space with norm (or more generally, if it is a seminormed space and is merely a seminorm),[note 2] then this list may be extended to include:

  1. B is a norm bounded subset of (X,). By definition, this means that there exists a real number r>0 such that br for all bB.Template:Sfn
  2. supbBb<.
    • Thus, if L:(X,)(Y,) is a linear map between two normed (or seminormed) spaces and if B is the closed (alternatively, open) unit ball in (X,) centered at the origin, then L is a bounded linear operator (which recall means that its operator norm L:=supbBL(b)< is finite) if and only if the image L(B) of this ball under L is a norm bounded subset of (Y,).
  3. B is a subset of some (open or closed) ball.[note 3]
    • This ball need not be centered at the origin, but its radius must (as usual) be positive and finite.

If B is a vector subspace of the TVS X then this list may be extended to include:

  1. B is contained in the closure of {0}.Template:Sfn
    • In other words, a vector subspace of X is bounded if and only if it is a subset of (the vector space) clX{0}.
    • Recall that X is a Hausdorff space if and only if {0} is closed in X. So the only bounded vector subspace of a Hausdorff TVS is {0}.

A subset that is not bounded is called Template:Em.

Bornology and fundamental systems of bounded sets

The collection of all bounded sets on a topological vector space X is called the Template:Em or the (Template:Em) Template:Em

A Template:Em or Template:Em of X is a set of bounded subsets of X such that every bounded subset of X is a subset of some B.Template:Sfn The set of all bounded subsets of X trivially forms a fundamental system of bounded sets of X.

Examples

In any locally convex TVS, the set of closed and bounded disks are a base of bounded set.Template:Sfn

Examples and sufficient conditions

Unless indicated otherwise, a topological vector space (TVS) need not be Hausdorff nor locally convex.

  • Finite sets are bounded.Template:Sfn
  • Every totally bounded subset of a TVS is bounded.Template:Sfn
  • Every relatively compact set in a topological vector space is bounded. If the space is equipped with the weak topology the converse is also true.
  • The set of points of a Cauchy sequence is bounded, the set of points of a Cauchy net need not be bounded.
  • The closure of the origin (referring to the closure of the set {0}) is always a bounded closed vector subspace. This set clX{0} is the unique largest (with respect to set inclusion ) bounded vector subspace of X. In particular, if BX is a bounded subset of X then so is B+clX{0}.

Unbounded sets

A set that is not bounded is said to be unbounded.

Any vector subspace of a TVS that is not a contained in the closure of {0} is unbounded

There exists a Fréchet space X having a bounded subset B and also a dense vector subspace M such that B is Template:Em contained in the closure (in X) of any bounded subset of M.Template:Sfn

Stability properties

Properties

Template:See also

A locally convex topological vector space has a bounded neighborhood of zero if and only if its topology can be defined by a Template:Em seminorm.

The polar of a bounded set is an absolutely convex and absorbing set.

Template:Math theorem

Using the definition of uniformly bounded sets given below, Mackey's countability condition can be restated as: If B1,B2,B3, are bounded subsets of a metrizable locally convex space then there exists a sequence t1,t2,t3, of positive real numbers such that t1B1,t2B2,t3B3, are uniformly bounded. In words, given any countable family of bounded sets in a metrizable locally convex space, it is possible to scale each set by its own positive real so that they become uniformly bounded.

Generalizations

Uniformly bounded sets

Template:See also

A family of sets of subsets of a topological vector space Y is said to be Template:Em in Y, if there exists some bounded subset D of Y such that BD for every B, which happens if and only if its union :=BB is a bounded subset of Y. In the case of a normed (or seminormed) space, a family is uniformly bounded if and only if its union is norm bounded, meaning that there exists some real M0 such that bM for every b, or equivalently, if and only if supBbBb<.

A set H of maps from X to Y is said to be Template:Em CX if the family H(C):={h(C):hH} is uniformly bounded in Y, which by definition means that there exists some bounded subset D of Y such that h(C)D for all hH, or equivalently, if and only if H(C):=hHh(C) is a bounded subset of Y. A set H of linear maps between two normed (or seminormed) spaces X and Y is uniformly bounded on some (or equivalently, every) open ball (and/or non-degenerate closed ball) in X if and only if their operator norms are uniformly bounded; that is, if and only if suphHh<.

Template:Math theorem

Template:Collapse top Assume H is equicontinuous and let W be a neighborhood of the origin in Y. Since H is equicontinuous, there exists a neighborhood U of the origin in X such that h(U)W for every hH. Because C is bounded in X, there exists some real r>0 such that if tr then CtU. So for every hH and every tr, h(C)h(tU)=th(U)tW, which implies that hHh(C)tW. Thus hHh(C) is bounded in Y. Q.E.D. Template:Collapse bottom

Template:Collapse top Let W be a balanced neighborhood of the origin in Y and let V be a closed balanced neighborhood of the origin in Y such that V+VW. Define E:=hHh1(V), which is a closed subset of X (since V is closed while every h:XY is continuous) that satisfies h(E)V for every hH. Note that for every non-zero scalar n0, the set nE is closed in X (since scalar multiplication by n0 is a homeomorphism) and so every CnE is closed in C.

It will now be shown that CnnE, from which C=n(CnE) follows. If cC then H(c) being bounded guarantees the existence of some positive integer n=nc such that H(c)ncV, where the linearity of every hH now implies 1ncch1(V); thus 1ncchHh1(V)=E and hence CnnE, as desired.

Thus C=(C1E)(C2E)(C3E) expresses C as a countable union of closed (in C) sets. Since C is a nonmeager subset of itself (as it is a Baire space by the Baire category theorem), this is only possible if there is some integer n such that CnE has non-empty interior in C. Let kIntC(CnE) be any point belonging to this open subset of C. Let U be any balanced open neighborhood of the origin in X such that C(k+U)IntC(CnE).

The sets {k+pU:p>1} form an increasing (meaning pq implies k+pUk+qU) cover of the compact space C, so there exists some p>1 such that Ck+pU (and thus 1p(Ck)U). It will be shown that h(C)pnW for every hH, thus demonstrating that {h(C):hH} is uniformly bounded in Y and completing the proof. So fix hH and cC. Let z:=p1pk+1pc.

The convexity of C guarantees zC and moreover, zk+U since zk=1pk+1pc=1p(ck)1p(Ck)U. Thus zC(k+U), which is a subset of IntC(CnE). Since nV is balanced and |1p|=p1<p, we have (1p)nVpnV, which combined with h(E)V gives pnh(E)+(1p)nh(E)pnV+(1p)nVpnV+pnVpn(V+V)pnW. Finally, c=pz+(1p)k and k,znE imply h(c)=ph(z)+(1p)h(k)pnh(E)+(1p)nh(E)pnW, as desired. Q.E.D. Template:Collapse bottom

Since every singleton subset of X is also a bounded subset, it follows that if HL(X,Y) is an equicontinuous set of continuous linear operators between two topological vector spaces X and Y (not necessarily Hausdorff or locally convex), then the orbit H(x):={h(x):hH} of every xX is a bounded subset of Y.

Bounded subsets of topological modules

The definition of bounded sets can be generalized to topological modules. A subset A of a topological module M over a topological ring R is bounded if for any neighborhood N of 0M there exists a neighborhood w of 0R such that wAB.

See also

References

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Notes

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Bibliography

Template:Functional analysis Template:Boundedness and bornology Template:Topological vector spaces


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