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...>. The disjunction operation follows from the identity <math>x \lor y = x \land y \oplus x \oplus y</math>.<ref name="Kap">Yu. V. Kapitonova, S.L. Krivoj, ...h>x \land ( y \land z) = (x \land y) \land z</math>, <math>x \land y = y \land x</math> ...

| symbolic statement = <math>(P \rightarrow Q) \land (P \rightarrow \neg Q) \rightarrow \neg P </math> This can be written as: <math>(P \rightarrow Q) \land (P \rightarrow \neg Q) \rightarrow \neg P </math> ...

...last1=Mead |first1=R. |last2=Willey |first2=R. W. |title=The Concept of a 'Land Equivalent Ratio' and Advantages in Yields from Intercropping |journal=Expe [[File:Land Equivalent Ratio v2 0 simple.png|upright=1.0|thumb|left|Land equivalent ratio]] ...

...used to reason about the correctness of computer programs. Its operators use pattern matching to operate on the [[power set]] of states, rather than the * The intersection of two patterns: <math>p_1 \land p_2</math> ...

The naive approach is to write the circuit as a Boolean expression, and use [[De Morgan's laws|De Morgan's law]] and the [[distributive property]] to c :<math>\phi := ((p \lor q) \land r) \to (\neg s)</math> ...

...require a dedicated link. This meant that mobile subscribers who wanted to use GPRS whilst roaming could only do so if their operator had a direct agreeme ...ion) developed the idea of GRX to handle all roaming between [[PLMN|public land mobile networks]] (PLMNs).<ref>{{cite web|url=http://www.gsma.com/newsroom/ ...

: <math>Y = \overline{(A \lor B) \land C} </math> : <math>Y = \overline{(A \lor B) \land (C \lor D)} </math> ...

Here we will use the set theory convention, where a filter <math>\mathcal{F}</math> on a set ...ultrafilter, the two quantifiers defined above coincide, and we will often use the notation <math>\mathcal{F} x</math> instead. Verbally, we might pronoun ...

The formulations here use implication and negation <math>\{\to,\neg\}</math> as functionally complete ...complete set <math>\{\neg,\lor\}</math> of connectives. These formulations use the following rule of inference; ...

...ctives are treated syncategorematically. Let us take the connective <math>\land</math> for instance. Its semantic rule is: : <math>\lVert \phi \land \psi \rVert = 1</math> iff <math>\lVert \phi \rVert = \lVert \psi \rVert = ...

...atical logic]]. Her results on Boolean formulas written in terms of <math>\land</math>, <math>\lor</math>, and <math>\lnot</math> were influential in the t :<math>f(x_1, x_2, x_3) = (x_1 \lor x_2 \lor x_3) \land (\lnot x_1 \lor x_2) \land (x_1 \lor \lnot x_3)</math>. ...

:<math>\neg(x < y \land y < x)</math> ...eg\psi)</math> as well as <math>\neg(\phi\lor\psi)\leftrightarrow(\neg\phi\land\neg\psi)</math>. The negation of the pseudo-order <math>x<y</math> of two e ...

...olean expression tree equivalent to ((true <math>\lor</math> false) <math>\land</math> <math>\neg</math>false) <math>\lor</math> (true <math>\lor</math> fa ...'true'' and ''false'' as constant values, and the operators include <math>\land</math> ([[Logical and|AND]]), <math>\lor</math> ([[Logical or|OR]]), <math> ...

Unlike logic programming, narrowing of algebraic value sets makes no use of [[backtracking]]. Instead all values are contained in value sets, and a The approach is also similar to the use of [[Constraint satisfaction|constraints]]<ref> ...

{{use dmy dates|date=April 2017}} {{use Indian English|date=April 2017}} ...

...nn diagrams require either extension into higher spatial dimensions or the use of more complicated shapes while Randolph diagrams evenly subdivide for eve ...ment introduced. Randolph's paper suggests that his original notion was to use R-diagrams to represent logical relationships, and then expanded the idea t ...

...many functional languages to allow the local definition of expression, for use in defining another expression. The let-expression is present in some func A "let" expression defines a function or value for use in another expression. As well as being a construct used in many functiona ...

...\{I \land C\}\;S\;\{I\}} {\{I\}\;\mathtt{while}\;C\; \mathtt{do}\; S \;\{I\land\lnot C\}},</math> :<math>\frac{< \text{ is well-founded},\;[I \land C \land V=z ]\;S\;[I \land V < z]} ...

...usual in first-order logic using propositional connectives such as <math>\land, \lor, \lnot</math> and quantifiers <math>\forall,\exists</math>. (\exists p,q,r.\ p \neq q \land p \neq r \land q \neq r) ...

...>, and so <math>(P\to Q)\to P</math> is equivalent to <math>(P\to Q)\to (P\land Q)</math>. The case <math>Q=\bot</math> now directly shows how double-negat In intuitionistic logic, explosion can be used for <math>\bot\to(P\land\bot)</math>, and so here the law's special case consequentia mirabilis also ...