Cauchy's estimate

From testwiki
Revision as of 12:28, 6 December 2024 by imported>John of Reading (Related estimate: Typo fixing, replaced: that that a → that a)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

In mathematics, specifically in complex analysis, Cauchy's estimate gives local bounds for the derivatives of a holomorphic function. These bounds are optimal.

Cauchy's estimate is also called Cauchy's inequality, but must not be confused with the Cauchy–Schwarz inequality.

Statement and consequence

Let f be a holomorphic function on the open ball B(a,r) in . If M is the sup of |f| over B(a,r), then Cauchy's estimate says:[1] for each integer n>0,

|f(n)(a)|n!rnM

where f(n) is the n-th complex derivative of f; i.e., f=fz and f(n)=(f(n1))' (see Template:Section link).

Moreover, taking f(z)=zn,a=0,r=1 shows the above estimate cannot be improved.

As a corollary, for example, we obtain Liouville's theorem, which says a bounded entire function is constant (indeed, let r in the estimate.) Slightly more generally, if f is an entire function bounded by A+B|z|k for some constants A,B and some integer k>0, then f is a polynomial.[2]

Proof

We start with Cauchy's integral formula applied to f, which gives for z with |za|<r,

f(z)=12πi|wa|=rf(w)wzdw

where r<r. By the differentiation under the integral sign (in the complex variable),[3] we get:

f(n)(z)=n!2πi|wa|=rf(w)(wz)n+1dw.

Thus,

|f(n)(a)|n!M2π|wa|=r|dw||wa|n+1=n!Mrn.

Letting rr finishes the proof.

(The proof shows it is not necessary to take M to be the sup over the whole open disk, but because of the maximal principle, restricting the sup to the near boundary would not change M.)

Here is a somehow more general but less precise estimate. It says:[4] given an open subset U, a compact subset KU and an integer n>0, there is a constant C such that for every holomorphic function f on U,

supK|f(n)|CU|f|dμ

where dμ is the Lebesgue measure.

This estimate follows from Cauchy's integral formula (in the general form) applied to u=ψf where ψ is a smooth function that is =1 on a neighborhood of K and whose support is contained in U. Indeed, shrinking U, assume U is bounded and the boundary of it is piecewise-smooth. Then, since u/z=fψ/z, by the integral formula,

u(z)=12πiUu(z)wzdw+12πiUf(w)ψ/w(w)wzdwdw

for z in U (since K can be a point, we cannot assume z is in K). Here, the first term on the right is zero since the support of u lies in U. Also, the support of ψ/w is contained in UK. Thus, after the differentiation under the integral sign, the claimed estimate follows.

As an application of the above estimate, we can obtain the Stieltjes–Vitali theorem,[5] which says that a sequence of holomorphic functions on an open subset U that is bounded on each compact subset has a subsequence converging on each compact subset (necessarily to a holomorphic function since the limit satisfies the Cauchy–Riemann equations). Indeed, the estimate implies such a sequence is equicontinuous on each compact subset; thus, Ascoli's theorem and the diagonal argument give a claimed subsequence.

In several variables

Cauchy's estimate is also valid for holomorphic functions in several variables. Namely, for a holomorphic function f on a polydisc U=1nB(aj,rj)n, we have:[6] for each multiindex αn,

|(zαf)(a)|α!rαsupU|f|

where a=(a1,,an), α!=αj! and rα=rjαj.

As in the one variable case, this follows from Cauchy's integral formula in polydiscs. Template:Section link and its consequence also continue to be valid in several variables with the same proofs.[7]

See also

References

Template:Reflist

Further reading


Template:Analysis-stub