Testwiki:Reference desk/Archives/Mathematics/2022 January 12

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January 12

The sign of harmonic addition theorem

Template:Resolved mark

Template:Plain link has the following equations Template:NumBlk Template:NumBlk given that a0. In addition, the following equation can be found in the Template:Plain link Template:NumBlk which implies Template:NumBlk Now, consider the case Template:NumBlk Template:NumBlk According to Template:EquationNote and Template:EquationNote, c should be positive. According to Template:EquationNote, Template:EquationNote and Template:EquationNote, c should be negative. Aforementioned results of c seem to be inconsistent. So what mistakes have I made? - Justin545 (talk) 17:36, 12 January 2022 (UTC)

Equation Template:EquationNote is accompanied by φ=arctan(b/a). The function arctan is in principle multivalued, but its value is conventionally restricted to π/2<φ<π/2. The sign of c comes from that convention. In your equation Template:EquationNote you break that convention, and if you insist on breaking it, then you must switch the sign in Template:EquationNote. --Wrongfilter (talk) 18:17, 12 January 2022 (UTC)
Thanks you for the help. Indeed, signs of a and c are the same if π/2<φ<π/2. And it seems signs of a and c are different if π/2<φ<3π/2. So, if I understand correctly, how about rewrite Template:EquationNote as

Template:NumBlk

in order to make sure Template:EquationNote and Template:EquationNote are consistent for all angles. - Justin545 (talk) 20:04, 12 January 2022 (UTC)
Or maybe replace a in Template:EquationNote by the RHS of Template:EquationNote:

Template:NumBlk

given that cosφ0 - Justin545 (talk) 20:13, 12 January 2022 (UTC)
I'm not sure what you're really trying to achieve and for some reason you always omit the second equation φ=arctan(b/a) (or tanφ=b/a, if you prefer). You need two equations to find (c,φ). --Wrongfilter (talk) 20:31, 12 January 2022 (UTC)
Okay, those are thoughtless replies. I am sorry for bothering you with the replies. - Justin545 (talk) 20:51, 12 January 2022 (UTC)