Testwiki:Reference desk/Archives/Mathematics/2016 September 4

From testwiki
Revision as of 01:05, 11 September 2016 by imported>Scsbot (edited by robot: archiving September 4)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

Template:Error:not substituted

{| width = "100%"

|- ! colspan="3" align="center" | Mathematics desk |- ! width="20%" align="left" | < September 3 ! width="25%" align="center"|<< Aug | September | Oct >> ! width="20%" align="right" |Current desk > |}

Welcome to the Wikipedia Mathematics Reference Desk Archives
The page you are currently viewing is a transcluded archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages.


September 4

Translation of Bourbaki to English

Bourbaki's Algebra chapters 1–3 and 4–7 have been translated to English. Were the remaining chapters translated (most particularly Template:Citation)? —Quondum 01:29, 4 September 2016 (UTC)

The probability that n experiments have k successes, when the success probability is p,

Pk=(nk)pk(1p)nk

satisfies the formula

Pk+1Pk=nkk+1p1p

I wonder how the latter formula can be proved without reference to the former formula?

Bo Jacoby (talk) 18:01, 4 September 2016 (UTC).

I have not gone through the details, but it seems promising to me to use the simple (i.e. obvious) rule of recursion
Pn,k=pPn1,k1+(1p)Pn1,k
plus suitable boundary conditions, and then use your formula with induction. By "boundary conditions", I am referring to the cases k=0 and k=n, which must be proved separately. —Quondum 21:19, 4 September 2016 (UTC)