Order bound dual: Difference between revisions

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Template:Short description In mathematics, specifically in order theory and functional analysis, the order bound dual of an ordered vector space X is the set of all linear functionals on X that map order intervals, which are sets of the form [a,b]:={xX:ax and xb}, to bounded sets.Template:Sfn The order bound dual of X is denoted by Xb. This space plays an important role in the theory of ordered topological vector spaces.

Canonical ordering

An element g of the order bound dual of X is called positive if x0 implies Re(f(x))0. The positive elements of the order bound dual form a cone that induces an ordering on Xb called the Template:Visible anchor. If X is an ordered vector space whose positive cone C is generating (meaning X=CC) then the order bound dual with the canonical ordering is an ordered vector space.Template:Sfn

Properties

The order bound dual of an ordered vector spaces contains its order dual.Template:Sfn If the positive cone of an ordered vector space X is generating and if for all positive x and x we have [0,x]+[0,y]=[0,x+y], then the order dual is equal to the order bound dual, which is an order complete vector lattice under its canonical ordering.Template:Sfn

Suppose X is a vector lattice and f and g are order bounded linear forms on X. Then for all xX,Template:Sfn

  1. sup(f,g)(|x|)=sup{f(y)+g(z):y0,z0, and y+z=|x|}
  2. inf(f,g)(|x|)=inf{f(y)+g(z):y0,z0, and y+z=|x|}
  3. |f|(|x|)=sup{f(yz):y0,z0, and y+z=|x|}
  4. |f(x)||f|(|x|)
  5. if f0 and g0 then f and g are lattice disjoint if and only if for each x0 and real r>0, there exists a decomposition x=a+b with a0,b0, and f(a)+g(b)r.

See also

References

Template:Reflist Template:Reflist

Template:Ordered topological vector spaces Template:Functional analysis