View source for Escape velocity

{{short description|Concept in celestial mechanics}}
{{Other uses|Escape Velocity (disambiguation){{!}}Escape Velocity}}
{{Distinguish|Orbital speed}}
{{Use dmy dates|date=May 2020}}
{{Astrodynamics}}
{{Spaceflight sidebar}}
In [[celestial mechanics]], '''escape velocity''' or '''escape speed''' is the minimum speed needed for an object to escape from contact with or orbit of a [[Primary (astronomy)|primary body]], assuming:
* [[Ballistic trajectory]] – no other forces are acting on the object, such as [[propulsion]] and [[friction]]
* No other gravity-producing objects exist.

Although the term ''escape velocity'' is common, it is more accurately described as a [[speed]] than as a [[velocity]] because it is independent of direction. Because gravitational force between two objects depends on their combined mass, the escape speed also depends on mass. For [[artificial satellite]]s and small natural objects, the mass of the object makes a negligible contribution to the combined mass, and so is often ignored.

Escape speed varies with distance from the center of the primary body, as does the velocity of an object traveling under the gravitational influence of the primary. If an object is in a circular or elliptical orbit, its speed is always less than the escape speed at its current distance. In contrast if it is on a [[hyperbolic trajectory]] its speed will always be higher than the escape speed at its current distance. (It will slow down as it gets to greater distance, but do so [[asymptotically]] approaching a positive speed.) An object on a [[parabolic trajectory]] will always be traveling exactly the escape speed at its current distance. It has precisely balanced positive [[kinetic energy]] and negative [[gravitational potential energy]];{{efn|Gravitational potential energy is defined to be zero at an infinite distance.}} it will always be slowing down, asymptotically approaching zero speed, but never quite stop.<ref>{{Cite book |last=Giancoli |first=Douglas C. |url=https://books.google.com/books?id=xz-UEdtRmzkC&pg=PA199 |title=Physics for Scientists and Engineers with Modern Physics |publisher=[[Addison-Wesley]] |year=2008 |isbn=978-0-13-149508-1 |page=199}}</ref>

Escape velocity calculations are typically used to determine whether an object will remain in the [[Sphere of influence (astrodynamics)|gravitational sphere of influence]] of a given body. For example, in [[solar system exploration]] it is useful to know whether a probe will continue to orbit the Earth or escape to a [[heliocentric orbit]]. It is also useful to know how much a probe will need to slow down in order to be [[gravitational capture|gravitationally captured]] by its destination body. Rockets do not have to reach escape velocity in a single maneuver, and objects can also use a [[gravity assist]] to siphon kinetic energy away from large bodies. 

Precise trajectory calculations require taking into account small forces like [[atmospheric drag]], [[radiation pressure]], and [[solar wind]]. A rocket under continuous or intermittent thrust (or an object climbing a [[space elevator]]) can attain escape at any non-zero speed, but the minimum amount of energy required to do so is always the same.

== Calculation ==
Escape speed at a distance ''d'' from the center of a spherically symmetric primary body (such as a star or a planet) with mass ''M'' is given by the formula<ref>{{cite book |title=New Understanding Physics for Advanced Level |author1=Jim Breithaupt |edition=illustrated |publisher=Nelson Thornes |year=2000 |isbn=978-0-7487-4314-8 |page=231 |url=https://books.google.com/books?id=r8I1gyNNKnoC}} [https://books.google.com/books?id=r8I1gyNNKnoC&pg=PA231 Extract of page 231]</ref><ref>{{cite book |title=Black Holes: A Very Short Introduction |author1=Katherine Blundell |edition=illustrated |publisher=Oxford University Press |year=2015 |isbn=978-0-19-960266-7 |page=4 |url=https://books.google.com/books?id=13PNCgAAQBAJ}} [https://books.google.com/books?id=13PNCgAAQBAJ&pg=PA4 Extract of page 4]</ref>
: <math>v_\text{e} = \sqrt{\frac{2GM}{d}} = \sqrt{2gd\ }</math>
where:
* ''G'' is the [[gravitational constant|universal gravitational constant]] ({{nowrap|''G'' ≈ {{physconst|G|round=2}}}})
* ''g'' = ''GM''/''d''<sup>2</sup> is the local gravitational acceleration (or the [[surface gravity]], when {{nowrap|1=''d'' = ''r''}}).

The value ''GM'' is called the [[standard gravitational parameter]], or ''μ'', and is often known more accurately than either ''G'' or ''M'' separately.

When given an initial speed ''V'' greater than the escape speed ''v''{{sub|e}}, the object will asymptotically approach the ''[[Hyperbolic trajectory|hyperbolic excess speed]]'' ''v''{{sub|∞}}, satisfying the equation:<ref>{{Cite book |last1=Bate |first1=Roger R. |url=https://books.google.com/books?id=UtJK8cetqGkC&pg=PA39 |title=Fundamentals of Astrodynamics |last2=Mueller |first2=Donald D. |last3=White |first3=Jerry E. |publisher=[[Courier Corporation]] |year=1971 |isbn=978-0-486-60061-1 |edition=illustrated |page=39}}</ref>
: <math>{v_\infty}^2 = V^2 - {v_\text{e}}^2 .</math>

For example, with the definitional value for [[standard gravity]] of {{convert|9.80665|m/s2|abbr=on}},<ref>{{cite book | last = Bureau International des Poids et Mesures | author-link = International Bureau of Weights and Measures | date = 1901 | title = Comptes Rendus des Séances de la Troisième Conférence· Générale des Poids et Mesures | section = Déclaration relative à l'unité de masse et à la définition du poids; valeur conventionnelle de {{math|''g''{{sub|n}}}} | url = https://www.bipm.org/fr/committees/cg/cgpm/3-1901/resolution-2 | location = Paris | publisher = Gauthier-Villars | page = 68 | language = FR | quote = Le nombre adopté dans le Service international des Poids et Mesures pour la valeur de l'accélération normale de la pesanteur est 980,665 cm/sec², nombre sanctionné déjà par quelques législations. Déclaration relative à l'unité de masse et à la définition du poids; valeur conventionnelle de {{math|''g''<sub>n</sub>}}.}}</ref> the escape velocity from Earth is {{convert|11.186|km/s|km/h mph ft/s|abbr=on}}.<ref>{{Cite book |last=Lai |first=Shu T. |url=https://books.google.com/books?id=JjrdCG5BFwUC&pg=PA240 |title=Fundamentals of Spacecraft Charging: Spacecraft Interactions with Space Plasmas |publisher=[[Princeton University Press]] |year=2011 |isbn=978-1-4008-3909-4 |page=240}}</ref> 

=== Energy required ===
For an object of mass <math>m</math> the energy required to escape the Earth's gravitational field is ''GMm''&nbsp;/&nbsp;''r'', a function of the object's mass (where ''r'' is [[Earth radius|radius of the Earth]], nominally 6,371 kilometres (3,959&nbsp;mi), ''G'' is the [[gravitational constant]], and ''M'' is the mass of the [[Earth]], {{nowrap|''M'' {{=}} 5.9736 × 10<sup>24</sup> kg}}). A related quantity is the [[specific orbital energy]] which is essentially the sum of the kinetic and potential energy divided by the mass. An object has reached escape velocity when the specific orbital energy is greater than or equal to zero.

=== Conservation of energy ===
[[Image:RIAN archive 510848 Interplanetary station Luna 1 - blacked.jpg|thumb|[[Luna 1]], launched in 1959, was the first artificial object to attain escape velocity from Earth.<ref>{{Cite web |url=https://nssdc.gsfc.nasa.gov/nmc/spacecraft/display.action?id=1959-012A |title=NASA – NSSDC – Spacecraft – Details<!-- Bot generated title --> |access-date=21 August 2019 |archive-date=2 June 2019 |archive-url=https://web.archive.org/web/20190602031816/https://nssdc.gsfc.nasa.gov/nmc/spacecraft/display.action?id=1959-012A |url-status=live }}</ref> (See [[List of Solar System probes]] for more.)]]

The existence of escape velocity can be thought of as a consequence of [[conservation of energy]] and an energy field of finite depth. For an object with a given total energy, which is moving subject to [[conservative force]]s (such as a static gravity field) it is only possible for the object to reach combinations of locations and speeds which have that total energy; places which have a higher potential energy than this cannot be reached at all. Adding speed (kinetic energy) to an object expands the region of locations it can reach, until, with enough energy, everywhere to infinity becomes accessible.

The formula for escape velocity can be derived from the principle of conservation of energy. For the sake of simplicity, unless stated otherwise, we assume that an object will escape the gravitational field of a uniform spherical planet by moving away from it and that the only significant force acting on the moving object is the planet's gravity. Imagine that a spaceship of mass ''m'' is initially at a distance ''r'' from the center of mass of the planet, whose mass is ''M'', and its initial speed is equal to its escape velocity, ''v''{{sub|e}}. At its final state, it will be an infinite distance away from the planet, and its speed will be negligibly small. [[Kinetic energy]] ''K'' and [[gravitational potential energy]] ''U''<sub>g</sub> are the only types of energy that we will deal with (we will ignore the drag of the atmosphere), so by the conservation of energy,
: <math>(K + U_\text{g})_\text{initial} = (K + U_\text{g})_\text{final}</math>

We can set ''K''<sub>final</sub> = 0 because final velocity is arbitrarily small, and {{nowrap|''U''<sub>g</sub>{{hsp}}<sub>final</sub>}} = 0 because final gravitational potential energy is defined to be zero a long distance away from a planet, so
: <math>\begin{align}
  \Rightarrow {} &\frac{1}{2}m{v_\text{e}}^2 + \frac{-GMm}{r} = 0 + 0 \\[3pt]
  \Rightarrow {} &v_\text{e} = \sqrt{\frac{2GM}{r}}
\end{align}</math>

=== Relativistic ===
The same result is obtained by a [[Theory of relativity|relativistic]] calculation, in which case the variable ''r'' represents the ''radial coordinate'' or ''reduced circumference'' of the [[Schwarzschild metric]].<ref>{{Cite book |last1=Taylor |first1=Edwin F. |url=https://books.google.com/books?id=y_waLQAACAAJ |title=Exploring Black Holes: Introduction to General Relativity |last2=Wheeler |first2=John Archibald |last3=Bertschinger |first3=Edmund |publisher=Addison-Wesley |year=2010 |isbn=978-0-321-51286-4 |edition=2nd revised |pages=2–22}} [http://www.eftaylor.com/pub/chapter2.pdf Sample chapter, page 2-22] {{Webarchive|url=https://web.archive.org/web/20170721192815/http://www.eftaylor.com/pub/chapter2.pdf |date=21 July 2017 }}</ref><ref>{{Cite book |last=Choquet-Bruhat |first=Yvonne |url=https://books.google.com/books?id=rOYwBQAAQBAJ&pg=PA116 |title=Introduction to General Relativity, Black Holes, and Cosmology |publisher=[[Oxford University Press]] |year=2015 |isbn=978-0-19-966646-1 |edition=illustrated |pages=116–117}}</ref>

== Scenarios ==

=== From the surface of a body ===
An alternative expression for the escape velocity ''v''{{sub|e}} particularly useful at the surface on the body is:
: <math>v_\text{e} = \sqrt{2gr}</math>
where ''r'' is the [[distance]] between the center of the body and the point at which escape velocity is being calculated and ''g'' is the [[gravitational acceleration]] at that distance (i.e., the [[surface gravity]]).<ref>Bate, Mueller and White, p. 35</ref>

For a body with a spherically symmetric distribution of mass, the escape velocity ''v''{{sub|e}} from the surface is proportional to the radius assuming constant density, and proportional to the square root of the average density ''ρ''.
: <math>v_\text{e} = Kr\sqrt\rho</math>
where <math display="inline">K = \sqrt{\frac{8}{3} \pi G} \approx \mathrm{2.364\times 10^{-5} ~m^{1.5}{\cdot}kg^{-0.5}{\cdot}s^{-1}} </math>.

This escape velocity is relative to a non-rotating frame of reference, not relative to the moving surface of the planet or moon, as explained below.

=== From a rotating body ===
The escape velocity ''relative to the surface'' of a rotating body depends on direction in which the escaping body travels. For example, as the Earth's rotational velocity is 465&nbsp;m/s at the [[equator]], a rocket launched tangentially from the Earth's equator to the east requires an initial velocity of about 10.735&nbsp;km/s ''relative to the moving surface at the point of launch'' to escape whereas a rocket launched tangentially from the Earth's equator to the west requires an initial velocity of about 11.665&nbsp;km/s ''relative to that moving surface''. The surface velocity decreases with the [[trigonometric function|cosine]] of the geographic latitude, so space launch facilities are often located as close to the equator as feasible, e.g. the American [[Cape Canaveral Air Force Station|Cape Canaveral]] (latitude 28°28&prime;&nbsp;N) and the French [[Guiana Space Centre]] (latitude 5°14&prime;&nbsp;N).

=== Practical considerations ===
In most situations it is impractical to achieve escape velocity almost instantly, because of the acceleration implied, and also because if there is an atmosphere, the hypersonic speeds involved (on Earth a speed of 11.2&nbsp;km/s, or 40,320&nbsp;km/h) would cause most objects to burn up due to [[aerodynamic heating]] or be torn apart by [[atmospheric drag]]. For an actual escape orbit, a spacecraft will accelerate steadily out of the atmosphere until it reaches the escape velocity appropriate for its altitude (which will be less than on the surface). In many cases, the spacecraft may be first placed in a [[parking orbit]] (e.g. a [[low Earth orbit]] at 160–2,000&nbsp;km) and then accelerated to the escape velocity at that altitude, which will be slightly lower (about 11.0&nbsp;km/s at a low Earth orbit of 200&nbsp;km). The required additional [[delta-v|change in speed]], however, is far less because the spacecraft already has a significant [[orbital speed]] (in low Earth orbit speed is approximately 7.8&nbsp;km/s, or 28,080&nbsp;km/h).

=== From an orbiting body ===
The escape velocity at a given height is <math>\sqrt 2</math> times the speed in a circular orbit at the same height, (compare this with the velocity equation in [[circular orbit]]). This corresponds to the fact that the potential energy with respect to infinity of an object in such an orbit is minus two times its kinetic energy, while to escape the sum of potential and kinetic energy needs to be at least zero. The velocity corresponding to the circular orbit is sometimes called the '''first cosmic velocity''', whereas in this context the escape velocity is referred to as the '''second cosmic velocity'''.<ref>{{Cite book |last=Teodorescu |first=P. P. |url=https://books.google.com/books?id=k4H2AjWh9qQC&pg=PA580 |title=Mechanical systems, classical models |publisher=Springer, Japan |year=2007 |isbn=978-1-4020-5441-9 |page=580}}, [https://books.google.com/books?id=k4H2AjWh9qQC&pg=PA580 Section 2.2.2, p. 580]</ref><ref>{{cite book |title=Physics of Planetary Ionospheres |author1=S. J. Bauer |edition=illustrated |publisher=Springer Science & Business Media |year=2012 |isbn=978-3-642-65555-5 |page=28 |url=https://books.google.com/books?id=ssPyCAAAQBAJ}} [https://books.google.com/books?id=ssPyCAAAQBAJ&pg=PA28 Extract of page 28]</ref><ref>{{cite book |title=Classical Mechanics in Geophysical Fluid Dynamics |author1=Osamu Morita |edition=2nd, illustrated |publisher=CRC Press |year=2022 |isbn=978-1-000-80250-4 |page=195 |url=https://books.google.com/books?id=cqAIEQAAQBAJ}} [https://books.google.com/books?id=cqAIEQAAQBAJ&pg=PA195 Extract of page 195]</ref>

For a body in an elliptical orbit wishing to accelerate to an escape orbit the required speed will vary, and will be greatest at [[periapsis]] when the body is closest to the central body. However, the orbital speed of the body will also be at its highest at this point, and the change in velocity required will be at its lowest, as explained by the [[Oberth effect]].

=== Barycentric escape velocity ===
Escape velocity can either be measured as relative to the other, central body or relative to [[center of mass|center of mass or barycenter]] of the system of bodies. Thus for systems of two bodies, the term ''escape velocity'' can be ambiguous, but it is usually intended to mean the barycentric escape velocity of the less massive body. Escape velocity usually refers to the escape velocity of zero mass [[test particles]]. For zero mass test particles we have that the 'relative to the other' and the 'barycentric' escape velocities are the same, namely <math>v_\text{e} = \sqrt{\frac{2GM}{d}} </math>.

But when we can't neglect the smaller mass (say ''m'') we arrive at slightly different formulas.

Because the system has to obey the [[Momentum#Conservation|law of conservation of momentum]] we see that both the larger and the smaller mass must be accelerated in the gravitational field. Relative to the center of mass the velocity of the larger mass (''v''{{sub|p}}, for planet) can be expressed in terms of the velocity of the smaller mass (''v''{{sub|r}}, for rocket). We get <math>v_p=-\frac{m}{M}v_r</math>.

The 'barycentric' escape velocity now becomes <math>v_r=\sqrt{\frac{2GM^2}{d(M+m)}} \approx \sqrt{\frac{2GM}{d}}</math>, while the 'relative to the other' escape velocity becomes <math> v_r -v_p=\sqrt{\frac{2G(m+M)}{d}} \approx \sqrt{\frac{2GM}{d}}</math>.

=== Height of lower-velocity trajectories ===
Ignoring all factors other than the gravitational force between the body and the object, an object projected vertically at speed ''v'' from the surface of a spherical body with escape velocity ''v''{{sub|e}} and radius ''R'' will attain a maximum height ''h'' satisfying the equation<ref>{{Cite book |last=Bajaj |first=N. K. |url=https://books.google.com/books?id=OLhyCgAAQBAJ |title=Complete Physics: JEE Main |publisher=[[McGraw-Hill Education]] |year=2015 |isbn=978-93-392-2032-7 |page=6.12}} [https://books.google.com/books?id=OLhyCgAAQBAJ&pg=SA6-PA12 Example 21, page 6.12]</ref>
: <math>v = v_\text{e} \sqrt{\frac{h}{R+h}} \ ,</math>
which, solving for ''h'' results in
: <math>h = \frac{x^2}{1-x^2} \ R \ ,</math>
where {{nowrap|1=''x'' = ''v''/''v''{{sub|e}}}} is the ratio of the original speed ''v'' to the escape velocity ''v''{{sub|e}}.

Unlike escape velocity, the direction (vertically up) is important to achieve maximum height.

== Trajectory ==
If an object attains exactly escape velocity, but is not directed straight away from the planet, then it will follow a curved path or trajectory. Although this trajectory does not form a closed shape, it can be referred to as an orbit. Assuming that gravity is the only significant force in the system, this object's speed at any point in the trajectory will be equal to the escape velocity ''at that point'' due to the conservation of energy, its total energy must always be 0, which implies that it always has escape velocity; see the derivation above. The shape of the trajectory will be a [[parabola]] whose focus is located at the center of mass of the planet. An actual escape requires a course with a trajectory that does not intersect with the planet, or its atmosphere, since this would cause the object to crash. When moving away from the source, this path is called an [[escape orbit]]. Escape orbits are known as {{nowrap|1=''C''{{sub|3}} = 0}} orbits. ''C''{{sub|3}} is the [[characteristic energy]], −''GM''/2''a'', where ''a'' is the [[semi-major axis]] length, which is infinite for parabolic trajectories.

If the body has a velocity greater than escape velocity then its path will form a [[hyperbolic trajectory]] and it will have an excess hyperbolic velocity, equivalent to the extra energy the body has. A relatively small extra [[delta-v|delta-''v'']] above that needed to accelerate to the escape speed can result in a relatively large speed at infinity. [[bi-elliptic transfer|Some orbital manoeuvres]] make use of this fact. For example, at a place where escape speed is 11.2&nbsp;km/s, the addition of 0.4&nbsp;km/s yields a hyperbolic excess speed of 3.02&nbsp;km/s:
: <math>v_\infty = \sqrt{ V^2 - {v_\text{e}}^2 } = \sqrt{ (11.6 \text{ km/s})^2 - (11.2 \text{ km/s})^2 } \approx 3.02 \text{ km/s}.</math>

If a body in circular orbit (or at the [[periapsis]] of an elliptical orbit) accelerates along its direction of travel to escape velocity, the point of acceleration will form the periapsis of the escape trajectory. The eventual direction of travel will be at 90 degrees to the direction at the point of acceleration. If the body accelerates to beyond escape velocity the eventual direction of travel will be at a smaller angle, and indicated by one of the asymptotes of the hyperbolic trajectory it is now taking. This means the timing of the acceleration is critical if the intention is to escape in a particular direction.

If the speed at periapsis is {{mvar|v}}, then the [[Eccentricity vector|eccentricity]] of the trajectory is given by:
: <math>e=2(v/v_\text{e})^2-1</math>
This is valid for elliptical, parabolic, and hyperbolic trajectories. If the trajectory is hyperbolic or parabolic, it will [[asymptotically]] approach an angle <math>\theta</math> from the direction at periapsis, with
: <math>\sin\theta=1/e.</math>
The speed will asymptotically approach
: <math>\sqrt{v^2-{v_\text{e}}^2}.</math>

== List of escape velocities ==
In this table, the left-hand half gives the escape velocity from the visible surface (which may be gaseous as with Jupiter for example), relative to the centre of the planet or moon (that is, not relative to its moving surface). In the right-hand half, ''V''<sub>e</sub> refers to the speed relative to the central body (for example the sun), whereas ''V''<sub>te</sub> is the speed (at the visible surface of the smaller body) relative to the smaller body (planet or moon).

{| class="wikitable"
! align=left  | Location
! align=left  | Relative to
! align=right | ''V''<sub>e</sub> (km/s)<ref name="EscapeVelocityData">For planets: {{Cite web |title=Planets and Pluto : Physical Characteristics |url=http://ssd.jpl.nasa.gov/?planet_phys_par |publisher=[[NASA]] |access-date=18 January 2017}}</ref>
| rowspan=21  |
! align=left  | Location
! align=left  | Relative to
! align=right | ''V''<sub>e</sub> (km/s)<ref name="EscapeVelocityData" />
! align=right | System escape, ''V''<sub>te</sub> (km/s)
|-
| On the [[Sun]] || The Sun's gravity || align=right| 617.5
| colspan=4 |
|-
| On [[Mercury (planet)|Mercury]] || Mercury's gravity || align=right| 4.25
| At Mercury || The Sun's gravity || align=right| ~ 67.7 || align=right| ~ 20.3
|-
| On [[Venus]] || Venus's gravity || align=right| 10.36
| At Venus || The Sun's gravity || align=right| 49.5 || align=right| 17.8
|-
| On [[Earth]] || Earth's gravity || align=right| 11.186
| At Earth || The Sun's gravity || align=right| 42.1 || align=right| 16.6
|-
| On the [[Moon]] || The Moon's gravity || align=right| 2.38
| At the Moon || Earth's gravity || align=right| 1.4 || align=right| 2.42
|-
| On [[Mars]] || Mars' gravity || align=right| 5.03
| At Mars || The Sun's gravity || align=right| 34.1 || align=right| 11.2
|-
| On [[Ceres (dwarf planet)|Ceres]] || Ceres's gravity || align=right| 0.51
| At Ceres || The Sun's gravity || align=right| 25.3 || align=right| 7.4
|-
| On [[Jupiter]] || Jupiter's gravity || align=right| 60.20
| At Jupiter || The Sun's gravity || align=right| 18.5 || align=right| 60.4
|-
| On [[Io (moon)|Io]] || Io's gravity || align=right| 2.558
| At Io || Jupiter's gravity || align=right| 24.5 || align=right| 7.6
|-
| On [[Europa (moon)|Europa]] || Europa's gravity || align=right| 2.025
| At Europa || Jupiter's gravity || align=right| 19.4 || align=right| 6.0
|-
| On [[Ganymede (moon)|Ganymede]] || Ganymede's gravity || align=right| 2.741
| At Ganymede || Jupiter's gravity || align=right| 15.4 || align=right| 5.3
|-
| On [[Callisto (moon)|Callisto]] || Callisto's gravity || align=right| 2.440
| At Callisto || Jupiter's gravity || align=right| 11.6 || align=right| 4.2
|-
| On [[Saturn]] || Saturn's gravity || align=right| 36.09
| At Saturn || The Sun's gravity || align=right| 13.6 || align=right| 36.3
|-
| On [[Titan (moon)|Titan]] || Titan's gravity || align=right| 2.639
| At Titan || Saturn's gravity || align=right| 7.8 || align=right| 3.5
|-
| On [[Uranus]] || Uranus' gravity || align=right| 21.38
| At Uranus || The Sun's gravity || align=right| 9.6 || align=right| 21.5
|-
| On [[Neptune]] || Neptune's gravity || align=right| 23.56
| At Neptune || The Sun's gravity || align=right| 7.7 || align=right| 23.7
|-
| On [[Triton (moon)|Triton]] || Triton's gravity || align=right| 1.455
| At Triton || Neptune's gravity || align=right| 6.2 || align=right| 2.33
|-
| On [[Pluto]] || Pluto's gravity || align=right| 1.23
| At Pluto || The Sun's gravity || align=right| ~ 6.6 || align=right| ~ 2.3
|-
| 200 AU from the Sun || The Sun's gravity || align=right| 2.98<ref name="i4is">{{cite web
  |title=To the Voyagers and escaping from the Sun
  |publisher=Initiative for Interstellar Studies
  |date=2015-02-25
  |url=https://i4is.org/voyagers-escaping-sun/
  |accessdate=2023-02-03}}</ref>
| rowspan=4 colspan=4 |
|-
| 1774 AU from the Sun || The Sun's gravity || align=right| 1<ref name="i4is"/>
|-
| At [[Solar System]] galactic radius || The [[Milky Way]]'s gravity || align=right| 492&ndash;594<ref>{{Cite journal |last1=Smith |first1=Martin C. |last2=Ruchti, G. R. |last3=Helmi, A. |last4=Wyse, R. F. G. |year=2007 |title=The RAVE Survey: Constraining the Local Galactic Escape Speed |journal=Proceedings of the International Astronomical Union |volume=2 |issue=S235 |pages=755–772 |arxiv=astro-ph/0611671 |doi=10.1017/S1743921306005692|bibcode=2007IAUS..235..137S |s2cid=125255461 }}</ref><ref name="Kafle2014">{{Cite journal |last1=Kafle |first1=P.R. |last2=Sharma |first2=S. |last3=Lewis |first3=G.F. |last4=Bland-Hawthorn |first4=J. |year=2014 |title=On the Shoulders of Giants: Properties of the Stellar Halo and the Milky Way Mass Distribution |journal=The Astrophysical Journal |volume=794 |issue=1 |pages=17 |arxiv=1408.1787 |bibcode=2014ApJ...794...59K |doi=10.1088/0004-637X/794/1/59|s2cid=119040135 }}</ref>
|-
| On the [[event horizon]] || A [[black hole]]'s gravity || align=right| >299,792.458 ([[speed of light]])
|}
The last two columns will depend precisely where in orbit escape velocity is reached, as the orbits are not exactly circular (particularly Mercury and Pluto).

== Deriving escape velocity using calculus ==
Let ''G'' be the [[gravitational constant]] and let ''M'' be the [[Earth mass|mass of the earth]] (or other gravitating body) and ''m'' be the mass of the escaping body or projectile. At a distance ''r'' from the centre of gravitation the body feels an attractive force
: <math>F = G\frac{Mm}{r^2}.</math>
The work needed to move the body over a small distance ''dr'' against this force is therefore given by
: <math>dW = F \, dr = G\frac{Mm}{r^2}\,dr.</math>
The total work needed to move the body from the surface ''r''<sub>0</sub> of the gravitating body to infinity is then<ref>{{cite book |title=A-level Physics |edition=illustrated |first1=Roger |last1=Muncaster |publisher=Nelson Thornes |year=1993 |isbn=978-0-7487-1584-8 |page=103 |url=https://books.google.com/books?id=Knov8XAyf2cC}} [https://books.google.com/books?id=Knov8XAyf2cC&pg=PA103 Extract of page 103]</ref>
: <math>W = \int_{r_0}^\infty G\frac{Mm}{r^2}\,dr  = G\frac{Mm}{r_0} = mgr_0.</math>
In order to do this work to reach infinity, the body's minimal kinetic energy at departure must match this work, so the escape velocity ''v''<sub>0</sub> satisfies
: <math> \frac{1}{2}m {v_0}^2 = G\frac{Mm}{r_0},</math>
which results in
: <math>v_0 = \sqrt\frac{2GM}{r_0} = \sqrt{2gr_0}.</math>

== See also ==
{{div col}}
* [[Black hole]] – an object with an escape velocity greater than the speed of light
* [[Characteristic energy]] (''C''<sub>3</sub>)
* [[Delta-v budget|Delta-''v'' budget]] – speed needed to perform maneuvers
* [[Gravity assist]] – a technique for changing trajectory
* [[Gravity well]]
* [[List of artificial objects in heliocentric orbit]]
* [[List of artificial objects leaving the Solar System]]
* [[Newton's cannonball]]
* [[Oberth effect]] – burning propellant deep in a gravity field gives higher change in kinetic energy
* [[Two-body problem]]
{{div col end}}

== Notes ==
{{notelist}}

== References ==
{{reflist}}

== External links ==
* [http://www.fxsolver.com/solve/share/GY3Qhzwd9hbCT-w6XDijwg==/ Escape velocity calculator]
* [http://www.calctool.org/CALC/phys/astronomy/escape_velocity Web-based numerical escape velocity calculator]

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